Answer 1)
a=1° = 0.01745329252 radiansExplanation : According to the conversion chart, to convert 1° this formula is used;
<span>radians = degrees × π / 180°
</span>
while solving for, One degree which is equal 0.01745329252 radians:
1° = π/180° = 0.005555556π = 0.01745329252 rad
Answer 2) b = 1' = = 0.0002907 radians
Explanation : A minute of arc is π/10800 of radian; which is a measurement unit of angular which is equal to 1/60 of 1° degree.
So substituting the value of 1° as and on solving we get,
0.01745/60 = 0.0002907 radians.
A minute of arc is <span>π/<span>10800</span></span><span> of a </span>radian.
Answer 3) C= 1'' = 4.8481
Explanation - When calculating second of arc which is considered to be 1/60 of an arc minute, and 1/3600 of a degree;
So all these are inter-related units which can be calculated if any one value is given;
<span>on solving we get, </span>π/648000 (about 1/206265) of a radian =
4.8481 X
Answer:
lithosphere
Explanation:
its found in the earth :)))
<u>Answer:</u> The enthalpy of the reaction is coming out to be -111.6 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28reactant%29%7D%5D)
The chemical equation for the reduction of acetaldehyde to ethanol follows:

The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(1\times \Delta H^o_f_{(CH_3CH_2OH(l))})]-[(1\times \Delta H^o_f_{(CH_3CHO(g))})+(1\times \Delta H^o_f_{(H_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CH_3CH_2OH%28l%29%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CH_3CHO%28g%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2%28g%29%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![\Delta H_{rxn}=[(1\times (-277.6))]-[(1\times (-166))+(1\times (0))]\\\\\Delta H_{rxn}=-111.6kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-277.6%29%29%5D-%5B%281%5Ctimes%20%28-166%29%29%2B%281%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D-111.6kJ)
Hence, the enthalpy of the reaction is coming out to be -111.6 kJ.
<span>The pressure on the inside of the mattress from air particles matches the force applied from the body.</span>
The correct answer is B) they operate at a higher efficiency. sorry hope the answers not to late :(