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nignag [31]
3 years ago
14

Name the property: i) (-15) X (-56)

Mathematics
1 answer:
gregori [183]3 years ago
3 0

Answer:

Open in answr appOpen_in_app

(i)

15

7

=

30

x

⇒x=

15

7×30

=14

(ii)

3

x

=

18

12

⇒x=

18

12×3

=2

(iii)

x

30

=

24

45

⇒x=

45

30×24

=16

(iv)

16

8

=

x

25

⇒x=

8

25×16

=50

Step-by-step explanation:

yeah

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Help anyone can help me do the question 4,I will mark brainlest.​
nasty-shy [4]

Answer:

Hello,

Step-by-step explanation:

A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\

8 0
3 years ago
Read 2 more answers
Help ;-;........ ;v;
iragen [17]

Answer:

$163

Step-by-step explanation:

Bob worked 26 hours and earn $7 per hour. Multiply 26 with 7:

26 x 7 = 182

Bob made a total of $182 last month.

Bob then spent $19. Subtract 19 from the total earned:

182 - 19 = 163

Bob has $163 left.

~

6 0
3 years ago
Read 2 more answers
Let m Z1=(3x)º, m 22=(5x-7)", m 23=(4x+15), and m ZAFD=128º. Find m44 and m ZBFD.​
olga55 [171]

Answer:

m<4 = 52°

m<BFD = 98°

Step-by-step explanation:

m<1 = (3x)°

m<2 = (5x - 7)°

m<3 = (4x + 15)°

m<AFD = 128°

✔️Find m<4:

m<4 = 180° - m<AFD (angles on a straight line)

Substitute

m<4 = 180° - 128°

m<4 = 52°

✔️m<BFD = m<2 + m<3

Substitute

m<BFD = (5x - 7)° + (4x + 15)°

We need to find the value of x.

Create an equation to find x.

m<1 + m<2 + m<3 = m<AFD (angle addition postulate)

Substitute

3x + 5x - 7 + 4x + 15 = 128°

Add like terms and solve for x

12x + 8 = 128

12x + 8 - 8 = 128 - 8

12x = 120

12x/12 = 120/12

x = 10

m<BFD = (5x - 7)° + (4x + 15)°

Plug in the value of x

m<BFD = 5(10) - 7 + 4(10) + 15

m<BFD = 50 - 7 + 40 + 15

m<BFD = 98°

4 0
3 years ago
Bro can someone help me plz
juin [17]

Answer:24 miles/50$

Step-by-step explanation:

thats what i got

5 0
3 years ago
Read 2 more answers
the standard for of the equation of a parabola is y=x^2+4x+11. What is the vertex for of the equation?
Eva8 [605]
Convert to vertex form

or easier
for y=ax²+bx+c
the x value of the vertex is \frac{-b}{2a}
and the y value is found by subsituting the x value in for x

so
y=1x²+4x+11
a=1
b=4

the x value of the vertex is \frac{-4}{2(1)}=\frac{-4}{2}=-2

the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7

the vertex is (-2,7)
6 0
3 years ago
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