The least positive value x for which tangent x equals 0tanx=0 is

Mathematics

2 answers:

Serggg [28]2 years ago

6 0

The only value for x to make tanx = 0 is either 0 or 180 or 0 or pi.

anastassius [24]2 years ago

4 0

Answer:

0° and 180°

Step-by-step explanation:

Given tanx = 0

To get all positive value of x,

Tanx = 0

x = tan^-1x

x = 0°

Since the angle is positive, another angle for x will be found in the 3rd quadrant because tan is positive in the third quadrant.

x = 180+theta(3rd quadrant)

x = 180+0

x = 180°

The least positive values of x are 0° and 180°

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Solve the equatuon<br><br> x/2-(2/(x+1))=1<br><br> x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$