The person who can give a short defination of subroutine will get the brainliest.

Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)

Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

8 0

3 years ago

Under which of the following conditions will evaluating this boolean expression

zzz [600]

1.)
((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) 

The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. 

For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. 

a.) (i <= n) || (i >= n) 

This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. 

b.) (a[i] == 0) && (a[i-1] == 0) 

This means that both of these terms are true. We substitute. 

((i <= n) && true) || (((i >= n) && true)) 

Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: 

(i <= n) || (i >= n) 

This is clearly always true.

3 0

3 years ago

Mrs. Zoo gave out the rubric for our essay. She stated that our essay should be complete by Friday of that week. I didn't have t

Rom4ik [11]

Answer:

No

Explanation:

You had the whole week for the essay but didn't do it and then turned it in late.

6 0

3 years ago

An initialization expression may be omitted from the for loop if no initialization is required.

stealth61 [152]

Answer:

True

Explanation:

for loop is used to repeat the process again and again until the condition not failed.

syntax:

for(initialize; condition; increment/decrement)

{

Statement

}

But we can omit the initialize or condition or increment/decrement as well

the syntax after omit the initialization,

for( ; condition; increment/decrement)

{

Statement

}

The above for loop is valid, it has no error.

Note: don't remove the semicolon.

You can omit the condition and increment/decrement.

and place the semicolon as it is. If you remove the semicolon, then the compiler show syntax error.

5 0

4 years ago

Do u like five nights at Freddy's? and is it good or bad?

Murljashka [212]

Answer:

its bad

Explanation:

6 0

3 years ago

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