The quantity of heat required to vapourize 1 mole of a substance depends on the kind of intermolecular forces between the molecules of the substance. Diethyl ether molecules are held together by weak dispersion forces compared to the stronger hydrogen bonding in ethanol. Therefore, 1 mole of diethyl ether requires less heat to vapourize than is required to vapourize 1 mole of ethanol.
Intermolecular forces hold the molecules a substance together in a given state of matter. The properties of a substance such as boiling point, melting point etc are dependent on the nature of intermolecular forces holding the molecules of the substance.
Diethyl ether molecules are held together by weak dispersion forces while molecules of ethanol are held together by hydrogen bonds.
Since hydrogen bonds are much stronger than dispersion forces, a greater quantity of heat is required to break the intermolecular hydrogen bonds in ethanol in order to vapourize them than is required to vapourize diethyl ether.
Therefore, owing to stronger intermolecular forces between molecules of ethanol, less heat is required to vapourize than is required to vapourize 1 mole of ethanol.
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Answer:
They would produce a repulsive force to another
Explanation:
A positive particle approaching another positive particle will repulse it.
According to coulomb's law "like charges repel one another and unlike charges attract".
A charge is an intrinsic property of any matter.
When like charges e.g positive and positive or negative and negative charges are in the vicinity of one another, they repel each other.
When unlike charges; positive and negative are brought together, they simply attract one another.
Therefore, we expect that a positive particle approaching another positive particle will repel one another.
Answer:
B. accepted value x 0.1
Explanation:
in the equation provided

Maximum allowed value of percentage error = 10%
put this value in the equation in stead of percentage error we get,

so maximum error = .1 x accepted value
10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value
or .1 times of accepted value