Answer:
6.8g of solute are needed
Explanation:
Percent by mass, (w/w%) is defined as the mass of solute in 100g of solution. A solution that is 3.4% contains 3.4g of solute in 100g of solution. That means to make 200g of solution are required:
200g solution * (3.4g solute / 100g solution) = 6.8g of solute are needed
<span>2 KClO3(s) → 3 O2(g) + 2 KCl(s)
</span><span>Note: MnO2 (Manganese Dioxide) is not part of the reaction. A catalyst lowers the activation energy and increases both forward and reverse reactions at equal rates.
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molar mass of KClO3 = 122.5
Moles of KClO3 = 3.45 / 122.55 = 0.028
Moles of O2 produce =

= 0.042 moles
molar mass of O2 = 32
so, mass of O2 = 32 x 0.042 = 1.35 g
Answer:
B
Explanation:
Carbon Dioxide is one of waste produced from Our cells during respiration. The circulatory system carries Carbon Dioxide from cells either in haemaglobin in RBC or plasm. The Carbon Dioxide being carried to blood cappilaries near alveoli before diffused into alveoli and then being removed away by respiratory system in the process of respiration while we exhale
The answer is Smog, hope this helps! pls mark brainliest! thanks!
They are called Periods. Lesser known as series