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marta [7]
3 years ago
5

Phosphorus trichloride, PCl3, decomposes to form elemental phosphorus and chlorine. The equation is: 4PCl3 → P4 + 6Cl2. Balance

the equation and determine the mass in grams of chlorine that would be formed if 25 grams of PCl3 (molecular mass = 137.32 g/mol) decompose. grams of Cl2
Chemistry
2 answers:
Scilla [17]3 years ago
8 0

answer- 19 grams of CI2

TiliK225 [7]3 years ago
5 0
19 grams of Cl2 is the correct answer                <span>

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d

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The titration of 25.00 ml a 0.125 m hclo4 solution requires 27.07 ml of koh to reach the endpoint. what is the concentration of
agasfer [191]

Answer : The concentration of the KOH is, 0.115 M

Explanation :

Using dilution law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 1

M_1 = concentration of HClO_4 = 0.125 M

M_2 = concentration of KOH = ?

V_1 = volume of HClO_4 = 25 ml

V_2 = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the KOH.

1\times 0.125M\times 25ml=1\times M_2\times 27.07ml

M_2=0.115M

Therefore, the concentration of the KOH is, 0.115 M

5 0
4 years ago
A student creates a solution by dissolving some Na2SO4 (molar mass = 142.05 g/mol) in enough water to create 0.500 L of solution
NeX [460]

Answer : The mass of Na_2SO_4 is, 4.43 grams.

Explanation :

As we know that, when Na_2SO_4 dissolve in water then it dissociates to give 2 mole of sodium ion Na^+ and 1 mole of sulfate ion SO_4^{2-}

The chemical reaction will be:

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

Thus, the concentration of Na_2SO_4 = \frac{\text{Concentration of }Na^+}{2}=\frac{0.125M}{2}=0.0625M

First we have to calculate the moles of Na_2SO_4

\text{Concentration of }Na_2SO_4=\frac{\text{Moles of }Na_2SO_4}{\text{Volume of solution}}

0.0625M=\frac{\text{Moles of }Na_2SO_4}{0.500L}

\text{Moles of }Na_2SO_4=0.0312mol

Now we have to calculate the mass of Na_2SO_4

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

Molar mass of Na_2SO_4 = 142 g/mol

\text{Mass of }Na_2SO_4=0.0312mol\times 142g/mol=4.43g

Thus, the mass of Na_2SO_4 is, 4.43 grams.

6 0
3 years ago
What are substances called whose solutions conduct electricity?
Shkiper50 [21]
It is called an electrolyte
4 0
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