Question

If the sum of four consecutive numbers is 854, what is the last one?

Answer 1

Answer:

The last one is 215

Step-by-step explanation:

Let

x ----> the first consecutive number

x+1 ---> the second consecutive number

x+2 ---> the third consecutive number

x+3 ----> the fourth consecutive number

we have that

$x+(x+1)+(x+2)+(x+3)=854$

solve for x

Combine like terms

$4x+6=854$

Subtract 6 both sides

$4x+6-6=854-6$

$4x=848$

Divide by 4 both sides

$x=212$

Find the last one

$x+3=212+3=215$

therefore

The last one is 215