An equilateral triangle has an apothem measuring 2.16 cm
2 answers:
Answer:
d) 24.2 cm²
<em>Area of equilateral triangle A = 24.22 cm²</em>
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
<em> Perimeter of equilateral triangle = 3 a</em>
Given Perimeter of equilateral triangle = 22.45 cm
now 3 a = 22.45
Dividing '3' on both sides,we get
a = 7.48 cm
<u><em>Step(ii):</em></u>-
<em>Area of equilateral triangle</em>
<em> </em><em></em>
<em> </em><em></em>
<em> A = 24.22 cm²</em>
<u><em>Conclusion</em></u><em>:-</em>
<em>Area of equilateral triangle A = 24.22 cm²</em>
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Answer:
The correct options are;
EFGH has 4 congruent sides
Diagonal FH bisects angles EFG and EHG
Angle FEH is congruent to angle FGH
Step-by-step explanation:
1) Given that for a reflection, we have;
The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection
Therefore;
The distance of the point E from the line HF = The distance of the point G from the line HF
Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)
We can show that from the length of a line given by the equation, that the length EH ≅ GH and EF ≅ GF
Therefore since we are given that EH = EF, we have;
EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides
2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;
ΔEHF ≅ ΔGHF
∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent
Similarly, ∠GFH ≅ ∠EFH
Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF
Therefore, diagonal FH bisects angles EFG and EHG
3) Given that ΔEHF ≅ ΔGHF, we have;
Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent