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makkiz [27]
3 years ago
10

Consider this reaction: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g).

Chemistry
1 answer:
iragen [17]3 years ago
5 0
Option are as follow,

A. temperature, concentration and surface area 
<span>B. temperature, and concentration only </span>
<span>C. concentration and surface area only </span>
<span>D. temperature and surface area only
</span>
Answer:
           Option-<span>A. Temperature, Concentration and Surface area
</span>
Explanation:

1) Increasing Temperature:
                                              Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.

2) Increasing Concentration
                                            Increase in concentration results in increase in number of particles of reactants per unit area, hence collision rate increases resulting in rate of reaction.

3) Increasing Surface Area
                                             Grinding of Zn results in the increase of surface area of Zinc. So greater the surface area greater is the exposure of Zinc metal to HCl molecules, hence the rate of formation of product increases.
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Determine the balanced chemical equation for this reaction.C8H18(g) O2(g)→CO2(g) H2O(g)Enter the coefficients for each compound
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An industrial chemist studying bleaching and sterilizing prepares several hypoclorite buffers.
Vanyuwa [196]

Answer:

pH is 7.60

Explanation:

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HClO + H₂O  ⇄  ClO⁻  +  H₃O⁺

As every weak acid, we make an equilbrium

The salt is dissociated in solution

NaClO → Na⁺  +  ClO⁻

                  HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

Initially       0.3m                            0.35m

We have the moles of acid, and the moles of conjugate base.

Reacts          x                                    X                  X

Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)

HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

0.3 - x                        0.35 + x           x

Let's make the expression for Ka

Ka = [ClO⁻] . [H₃O⁺]  /  [HClO]

(we don't add water, because it is included in Ka)

2.9x10⁻⁸ = (0.35+x).x  / (0.3-x)

Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3  and 0.35 +x =0.3

2.9x10⁻⁸ = (0.35)x  / (0.3)

(2.9x10⁻⁸ .  0.3) /0.35 = x

2.48x10⁻⁸ = x

This is [H₃O⁺]

For pH = - log [H₃O⁺]

pH = 7.60

3 0
3 years ago
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