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makkiz [27]
3 years ago
10

Consider this reaction: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g).

Chemistry
1 answer:
iragen [17]3 years ago
5 0
Option are as follow,

A. temperature, concentration and surface area 
<span>B. temperature, and concentration only </span>
<span>C. concentration and surface area only </span>
<span>D. temperature and surface area only
</span>
Answer:
           Option-<span>A. Temperature, Concentration and Surface area
</span>
Explanation:

1) Increasing Temperature:
                                              Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.

2) Increasing Concentration
                                            Increase in concentration results in increase in number of particles of reactants per unit area, hence collision rate increases resulting in rate of reaction.

3) Increasing Surface Area
                                             Grinding of Zn results in the increase of surface area of Zinc. So greater the surface area greater is the exposure of Zinc metal to HCl molecules, hence the rate of formation of product increases.
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Answer:

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3 years ago
the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to
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<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa

Hence, the new pressure will be 101.46 kPa.

3 0
3 years ago
What mass in grams of hydrogen is produced by the reaction of 2.0 g of magnesium? (Make sure to balance the reaction first)
denpristay [2]

Answer:

0.164541341 g H2

Explanation:

1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).

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2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.

  0.082270671 mol of Mg = 0.082270671 mol of H2

3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).

  0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2

* Answer can be rounded to your liking *

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