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andrew-mc [135]
3 years ago
6

Which statement about the earth atmosphere is true

Chemistry
1 answer:
liq [111]3 years ago
8 0
I believe it to be C

Explanation: The concentration of carbon dioxide in Earth’s atmosphere is currently at nearly 412 parts per million (ppm) and rising. This represents a 47 percent increase since the beginning of the Industrial Age, when the concentration was near 280 ppm, and an 11 percent increase since 2000, when it was near 370 ppm.
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For the reaction
sp2606 [1]

Answer:

n_{H_2}^{equilibrium}=0.393mol

Explanation:

Hello,

In this case, given the amounts of water and carbon dioxide we should invert the given reaction as hydrogen will be producted rather than consumed:

H_2O(g) + CO(g)\rightleftharpoons H_2(g) + CO_2(g)

Consequently, the equilibrium constant is also inverted:

Kc'=\frac{1}{Kc}=\frac{1}{0.534} =1.87

In such a way, we can now propose the law of mass action:

Kc'=\frac{[H_2][CO_2]}{[H_2O][CO]}

And we can express it in terms of the initial concentrations of the reactants and the change x due to the reaction extent:

Kc'=\frac{(x)(x)}{([H_2O]_0-x)([CO]_0-x)}=1.87

Thus, we compute the initial concentration which are same, since equal amount of moles are given:

[H_2O]_0=[CO]_0=\frac{0.680mol}{70.0L}=0.0097M

Hence, solving for x by using the quardratic equation or solver, we obtain:

x_1=0.00561M\\x_2=0.0361M

For which the correct value is 0.00561M since the other one will produce negative concentrations of water and carbon monoxide at equilibrium. Therefore, the number of moles of hydrogen at equilibrium for the same 70.0-L container turn out:

n_{H_2}^{equilibrium}=0.00561mol/L*70.0L=0.393mol

Best regards.

3 0
3 years ago
HELP PLEASE WITH 1 QUESTION.
Nata [24]
The activity series goes top to bottom, most active to least active elements, going: Li, K, Ba, Sr, Ca, Na, Mg, Mn, Zn, Fe, Cd, Co, Ni, Sn, Pb, H, Cu, Ag, Hg, Au. 

Thus, your list of metals would go from most reactive to least reactive: Li, K, Mg, Zn, Fe, Cu, Au
8 0
3 years ago
Which experimental feature of the MALDI-MS technique allows the separation of ions formed after the adduction of tissue molecule
34kurt

Answer:

The experimental feature of the MALDI-MS technique which allows the separation of ions formed after the adduction of tissue molecules:

B) Velocity of ions depends on the ion mass-to-charge ratio.

Explanation:

  • The option a is not correct as distance traveled by ions doesn't depend upon the ion charge rather it depends upon time for which you leave the sample to run.
  • The  option b is correct as velocity of ions depends on the ion mass-to-charge ratio because separation is done due to mass to charge ratio feature.
  • The option c is incorrect as time of travel is not inversely proportional to the ion-to-mass ratio because the ion will move across the gel until you stop the electric field.
  • The option d is not correct as electric field between MALDI plate and MS analyzer is though uniform but this feature doesn't allow the separation of ions.

6 0
3 years ago
What is the answer please tell me
Nastasia [14]

Answer:

you need to include the bottom portion, not enough info

Explanation:

5 0
3 years ago
Identify the bonds between atoms of each pair of elements as nonpolar covalent, moderately polar covenant, very covalent or ioni
Daniel [21]
In general, bonds with an electronegativity difference of 0-0.5 are nonpolar covalent, bonds with an EN difference of 0.5-2.0 are covalent, and anything above 2.0 is considered ionic.

To determine the bond types of the pairs of elements, we will need their EN values. We can subtract their EN values to find their EN difference.

H and Br: 2.96-2.20=0.76
Therefore a bond between H and Br would be moderately polar covalent.

Cl and F: 3.98-3.16=0.82
Therefore this bond is moderately polar covalent.

K and Cl: 3.16-0.82=2.34
Therefore this bond is ionic.

Li and O: 3.44-0.98=2.46
Therefore this bond is ionic.

Br and Br: Because these are the same element, meaning that they have the same EN value, we automatically know that their EN difference would be zero. Therefore, this bond is very covalent.

4 0
3 years ago
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