The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
a Answer:
Step-by-step explanation:
Answer:
- Won = 88 games
- Lost = 24 games
Step-by-step explanation:
The number of games for the session is 112 so all the wins and losses should add up to 112.
Assume that the number of times they lost is x. The number of times they won would then be: 16 + 3x
Total expression is therefore:
16 + 3x + x = 112
16 + 4x = 112
4x = 112 - 16
x = 96/4
x = 24
They lost 24 games. Number of games won is:
= 112 - 24
= 88 games
The only one that’s true there is A. Domain refers to x values and range is y values. Your domain is between -1 and 3 and your range starts at zero and increases infinitely upward.
