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Komok [63]
3 years ago
13

The table shows how much each fifth grade room earned from a bake sale.the money is going to be given to 6 different charities i

f each charity is given an equal amount about how much will each charity receive show how you estimated
Room Earnings
110............... 327
112................ 425
114................ 550
116................ 486
Mathematics
2 answers:
svp [43]3 years ago
6 0

Answer:

About $300.

Step-by-step explanation:

To estimate, we will round these values to the nearest hundred.

327 rounds to 300; 425 rounds to 400; 550 rounds to 600; 486 rounds to 500.

Together, these make

300+400+600+500 = 1800

There are 6 charities; dividing by 6, we have

1800/6 = 300

tester [92]3 years ago
3 0
327+425+550+486 is 1788 so to get the answer you need to divide it by 6
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Income East and West of the Mississippi
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Answer:

H0: μ1 = μ2

H1: μ1 ≠ μ2 ;

xbar1 - xbar2

Step-by-step explanation:

The Null hypothesis should state that there is no difference in average household income between those located east and west of the Mississippi

H0: μ1 = μ2

H1: μ1 ≠ μ2

Statistic from the sample that would be used to estimate difference

Statistic refers to the numerical characteristic derived from the sample.

To estimate the difference in the average household income between those located east and west of the Mississippi, we take the sample mean of the two groups

Group 1, East of Mississippi = xbar 1

Group 2, West of Mississippi River = xbar 2

xbar1 - xbar2

6 0
3 years ago
From a thin piece of cardboard 50 in. by 50 in., square corners are cut out so that the sides can be folded up to make a box. Wh
mixer [17]

Answer:

When dimension of box is 33.33 inches × 33.33 inches ×8.33  then its volume is maximum and is 9259.26 cubic inches.

Step-by-step explanation:

Let h be the length (in inches) of the square corners that has been cut out from the cardboard and that would be the height of the cardboard box.

Since the squares have been cut from cardboard, both sides of the cardboard would reduce by 2h.

Thus, The dimension of box is  (50 – 2h) × (50 – 2h) × h in dimensions.

The volume V of rectangular box = (Length × Breadth × Height) cubic inches.

V=(50-2h) \times (50-2h) \times h

V=(50-2h)^2 \times h  ..............(1)

Using (a-b)^2=a^2+b^2-2ab

V=h(2500+4h^2-200h)

V=2500h+4h^3-200h^2

For obtaining a box of maximum volume, maximize V as a function of h.


Differentiate both sides with respect to h,

\frac{dV}{dh}=2500+12h^2-400h

\frac{dV}{dh}=4(625+3h^2-100h)

Solving quadratic equation,625+3h^2-100h

\frac{dV}{dh}=4(3h^2-25h-75h+625)

\frac{dV}{dh}=4(h(3h-25)-25(3h-25))

\frac{dV}{dh}=4((h-25)(3h-25))

For maximum, \frac{dV}{dh}=0  

thus,4((h-25)(3h-25))=0

⇒ h= 25 or h=\frac{25}{3}

Now check (1) for h= 25 and h=\frac{25}{3}.

h= 25 is not possible as when h is 25 inches then length and breadth becomes 0.

When h=\frac{25}{3}.

(1) ⇒ V=(50-2(\frac{25}{3}))^2 \times\frac{25}{3}=9259.2592593  

This is the maximum volume the box can assume.

Thus, when dimension of box is 33.3 inches × 33.3 inches ×8.3  then its volume is maximum and is 9259.26 cubic inches.

6 0
3 years ago
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