3 years ago

Can someone help me?

Mathematics

1 answer:

Savatey [412]3 years ago

6 0

Answer:

4.5>2.89

Step-by-step explanation:

This question is asking for the comparison between the values of both numbers. 4.5 is greater than 2.89, and this can be written as 4.5>2.89

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3 years ago

Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

artcher [175]

For this case we must solve the following equation:

$\sqrt {4x ^ 2} - \sqrt {x ^ 2} = 6$

To solve we follow the steps below:

We square both sides of the equation squared:

$(\sqrt {4x ^ 2} - \sqrt {x ^ 2}) ^ 2 = 6 ^ 2\\(\sqrt {4x ^ 2}) ^ 2-2 (\sqrt {4x ^ 2}) (\sqrt {x ^ 2}) + (\sqrt {x ^ 2}) ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 2 * x ^ 2}) + x ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 4}) + x ^ 2 = 36\\4x ^ 2-2 (2x ^ 2) + x ^ 2 = 36\\4x ^ 2-4x ^ 2 + x ^ 2 = 36\\x ^ 2 = 36\\x = \pm \sqrt {36}\\x = \pm6$