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3 years ago

What happens when a candle burns?

Physics

1 answer:

slega [8]3 years ago

5 0

Answer:

oxygen is used up is the answer

Explanation:

These vaporized molecules are drawn up into the flame, where they react with oxygen from the air to create heat, light, water vapor (H2O) and carbon dioxide (CO2).

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A 15.7 kg block is dragged over a rough, horizontal surface by a constant force of 83.1 N

Kay [80]

Answer:

The work done by the 83.1 N force is 4687.5 J.

The magnitude of the work done by the force of friction is 1187.5 J.

Explanation:

Given:

Mass of the block, $m=15.7$ kg

Force acting on it, $F=83.1$ N

Angle of application of force, $\theta = 25.7$ °

Displacement of the block, $d=62.6$ m

Coefficient of friction, $\mu =0.161$

Acceleration due to gravity, $g=9.8$ m/s²

Work done by a force is given as:

$Work,W=F\times d\times \cos\theta$

So, work done by the constant force is given as:

$W_{force}=83.1\times 62.6\times \cos(25.7)\\W_{force}=4687.5\textrm{ J}$

Now, in order to find work done by friction, we need to evaluate friction.

For the vertical direction, the net force is zero as there is no vertical motion.

Therefore,

$N + F\sin\theta = mg\\ N = mg-F\sin\theta$

Frictional force is given as:

$f=\mu N=\mu (mg-F \sin \theta)=0.161\times ((15.7\times 9.8)-(83.1\times \sin(25.7))=18.97\textrm{ N}$

Now, friction acts in the direction opposite to the displacement. Thus, angle between frictional force and displacement is 180°.

Therefore, work done by friction is:

$W_{fric}=f\times d\times \cos\theta_f\\W_{fric}=12.72\times 62.6\times \cos(-180)\\W_{fric}=18.97\times 62.6\times -1\\W_{fric}=-1187.5\textrm{ J}$

Negative sign indicates that frictional force is acting opposite to motion.

So, the magnitude of the work done by the force of friction is 1187.5 J.

8 0

4 years ago

The mass of an electron is _______. What is it?

SOVA2 [1]

If a mass of a neutron is 1 the electron mass is 0.00054386734 and it's charge is negative. Hope this helps! ;)

5 0

3 years ago

Is this right?? Please help me. IT IS SOCIOLOGY!

inn [45]

Where is the picture???

6 0

3 years ago

A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. What is

SVEN [57.7K]

Answer:

12.2 m/s

Explanation:

Initial momentum = final momentum

In the x direction:

(900 kg) (15.0 m/s) = (900 kg + 750 kg) vx

vx = 8.18 m/s

In the y direction:

(750 kg) (20.0 m/s) = (900 kg + 750 kg) vy

vy = 9.09

The magnitude of the velocity is therefore:

v = √(vx² + vy²)

v = 12.2 m/s

7 0

3 years ago

Jeff, a snowboarder who weighs 1000 N, is practicing on a trampoline for an upcoming competition. As Jeff bounces straight up of

NISA [10]

Answer:

Potential energy $P_E = 2000 J$

Explanation:

Given data

Weight of the person = 1000 N

Mass of the person = $\frac{1000}{9.81} = 102 kg$

Speed = 6.26 $\frac{m}{s}$

Kinetic energy is given by

$E_K = \frac{1}{2} m v^{2}$

Put the values in above formula we get

$E_K = \frac{1}{2}(102) 6.26^{2}$

$E_K = 2000 J$

When the person reach top point then at this point the velocity is zero & kinetic energy at top point is equals to the potential energy.

Therefore potential energy

$P_E = 2000 J$

5 0

3 years ago