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Yuri [45]
3 years ago
13

According to the Central Limit Theorem, the probability distribution of the sum or average of a large random sample drawn with r

eplacement will be roughly normal, regardless of the distribution of the population from which the sample is drawn. Question 4.4. Note the statement about the sample being large and random. Is this sample large and random
Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

Step-by-step explanation:

The specific sample is not given but the key point is to know if the sample is large and random.

In other words, the inquiry that applies here is: "How to identify a large sample and a random sample"

A large sample is one which has a large number of elements or observations or values.

In a large sample size, N (the number of observations or values) is either equal to 30 or greater than 30.

A random sample is a sample which is drawn randomly from a population. A population is the whole body of items or individuals which the researcher's 'torchlight' is focused on. A sample is usually drawn from a population to make the work of the researcher to be possible or feasible.

We say a sample is drawn randomly from a population IF there is no bias or preference for particular items or individuals in the population.

If a sample is drawn with replacement, it means that after picking an item to derive data from, the researcher replaces the item in the population space BEFORE picking another item to derive data from.

Hence, all through the sample creation process, the population size stays constant.

Now, the Central Limit Theorem (which you have already defined) says "... regardless of the distribution of the population from which the sample is drawn".

This means "... whether the distribution of the population is negatively skewed, normal, or positively skewed.

So once the sample is large (gives a wide representation of the population), random, and drawn with replacement of items; the Central Limit Theorem applies!

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The manager of the toy store at the mall is curious about why nobody is buying the new robot toys. He's very annoyed because he
marin [14]

Answer: B

Step-by-step explanation: I believe it's B because if you're able to get the opinions of others about your store. You'll be able to see whats the customers are more interested in, so therefore be able to supply your store with stuff people are more intrigued in. (Let me know if I'm wrong, have a good day)

6 0
4 years ago
Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.
kogti [31]
Answer: 
x = 2

2x + 1 = -x +7           Add and subtract 
3x = 6                                divide
x = 2
3 0
4 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
3 years ago
Read 2 more answers
A video company randomly selected 100 of its subscribers and asked them how many hours of shows they watch per week. Of those su
Alik [6]

Answer:

1,135 people

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

Step-by-step explanation:

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

8 0
3 years ago
To find the quotient of 4 ÷ 1 8 , count the number of in four whole circles.
SSSSS [86.1K]

Answer:

what are u asking ?? I'm confused

5 0
3 years ago
Read 2 more answers
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