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Alik [6]
3 years ago
8

AD = 3x + 4 and CD = x + 6, what is the value of x?

Mathematics
1 answer:
lesantik [10]3 years ago
5 0
Your answer would be x = 1.

The rules for a kite shape is that two pairs are of equal length, which means we can say that AD = CD and thus form an equation:

3x + 4 = x + 6
- x
2x + 4 = 6
- 4
2x = 2
÷ 2
x = 1

I hope this helps!
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Penny's garden has alength of 16ft. and the width is 5 ft. with a rectangular fountain in the middle that measures 5 ft by 9 ft.
lilavasa [31]

First we need the whole garden:

16 x 5 = 80

Now we need to fountain:

5 x 9 = 45

Now to find our answer:

80 - 45 = 35

So our answer is B. 35ft²

4 0
3 years ago
I need help plzz its due TODAYYY
kobusy [5.1K]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

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3 years ago
Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, neg
Reika [66]
Square root 50 does not belong....all of the other numbers are rational numbers. square root 50 is irrational.
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3 years ago
Can someone please help me with my maths question​
DIA [1.3K]

Answer:

a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}

Collecting like terms gives;

\dfrac{m^{(3 + 4 - 6)}  \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n}

Collecting like terms gives;

x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )

x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

4 0
3 years ago
kaitlin received a $70 gift card for a coffee store. she used it in buying some coffee that cost $7.69 per pound. after buying t
aksik [14]
Kaitlin bought 4 pounds of coffee.

70-39.24=30.76
30.76 ÷ 7.69= 4
8 0
2 years ago
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