Question

Two planes leave an airport at the same time. Thier speeds are mph 130 and 150 mph, and the angle between thier courses is 36 degree. How far apart are they after 1.5 hours?

Answer 1

Answer:

132.89 miles

Step-by-step explanation:

Let plane A travel at 130 mph and plane B travel at 150 mph.

After 1.5 hours, the total distance traveled by each plane is:

$A = 1.5 *130\\A = 195\ miles\\B = 1.5 *150\\B = 225\ miles$

The law of cosines can be used to find the distance (D) between both planes as follows:

$D^2 = A^2+B^2-2AB*cos(36)\\D=\sqrt{195^2+225^2-(2*195*225*cos(36))}\\D=132.89\ miles$

They are 132.89 miles apart after 1.5 hours.