The required value of the acute angle x in a right angle triangle is 20. Option A is correct.
Given that
In a right triangle, the acute angles have a relationship,
sin (2x+4) = cos(46)
To determine the value of x
<h3>What are trigonometric equations?</h3>
These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operation.
sin (2x+4) = cos(46) - - - - - -(1)
Since,
cos(46) = cos (90 - 44)
cos(46) = sin (44)
put it in equation 1
sin (2x+4) = sin (44)
2x + 4 = 44
2x = 44 - 4
2x = 40
x = 20
Thus, the required value of the acute angle x in a right angle triangle is 20. Option A is correct.
Learn more about trigonometry equations here:
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Answer:
From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>. From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.
Step-by-step explanation:
- From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
- From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.
- From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
Error= 0.1/2, 0.05
4.8 + 0.05 = 4.85
6.3 + 0.05 = 6.35
4.85 x 6.35 = 30.7975 cm (when rounded, gives 30.80 cm).
The mixture contains 61.5% of water.
<u>Step-by-step explanation:</u>
Total parts = 4+ 2.5 = 6.5
Parts of water =4
parts of drink = 2.5
Percent of water in the mixture = 4 × 100/ 6.5
= 400/6.5
= 61.53%
It is rounded to the nearest tenth as 61.5%.
