Answer:
8.9 KJ
Explanation:
Given data:
Mass of strip = 251 g
Initial temperature = 22.8 °C
Final temperature = 75.9 °C
Specific heat capacity of granite = 0.67 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 75.9 °C - 22.8 °C
ΔT = 53.1 °C
Q = 251 g × 0.67 j/g.°C × 53.1 °C
Q = 8929.8 J
Jolue to KJ.
8929.8J ×1 KJ / 1000 J
8.9 KJ
Answer:
Second one
Explanation:
I think it's the second cause there's no energy w/o heat. So it's the second.
Answer:
18
Explaintion:
Hope you got it right
Answer:
the electricity dissipated, because of the time.
Explanation:
electricity dissipates.
Explanation:
First, let's convert 481 mmHg to atm:
1 atm --- 760 mmHg
x atm --- 481 mmHg
x = 0.63 atm
mmHg to Torr:
1 mmHg ---- 1 Torr
481 mmHg --- 481 Torr
481 Torr
mmHg to inHg
1 mmHg ---- 0.039 inHg
481 mmHg ---- y inHg
y = 18.8 inHg
mmHg to Pa
1 mmHg --- 133.322 Pa
481 mmHg ---- z
z = 64,128 Pa
Answer:
0.63 atm
481 Torr
18.8 inHg
64,128 Pa