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lina2011 [118]
3 years ago
8

Explain why this statement is false.“Because there is no change in composition during a physical change, the appearance of the s

ubstance will not change.”
Chemistry
1 answer:
Dmitry [639]3 years ago
4 0
It is false because
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Are there any choices? If there are none then I would say either organelles or cell membrane. 
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A balloon occupies 175 cm at 25.0 C. What volume will it occupy at 42.5 °C?
patriot [66]

175 cm³ instead of 175 cm.

Answer:

297.5 cm³

Explanation:

From the question;

Initial volume; V1 = 175 cm³

Initial temperature; T1 = 25°C

Final temperature; T2 = 42.5°C

From Charles law we can find the volume V2 from the equation;

V1/T1 = V2/T2

Making V2 the subject gives;

V2 = V1 × T2/T1

V2 = (175 × 42.5)/25

V2 = 297.5 cm³

4 0
3 years ago
Liquid Boiling point (K) Enthalpy of vaporization (kJ/mol) benzene 353.1 30.72 toluene 383.6 33.18 nonane 423.8 37.18 chloroform
nata0808 [166]

Answer :

(a) The compound benzene follow the Trouton's rule.

(b) The compound toluene follow the Trouton's rule.

(c) The compound nonane follow the Trouton's rule.

(d) The compound chloroform follow the Trouton's rule.

(e) The compound ethanol does not follow the Trouton's rule.

(f) The compound water does not follow the Trouton's rule.

Explanation :

Trouton's rule : According to this rule, the molar entropy of vaporization should be constant  that means,

\Delta S_{vap}=85-88J/K.mole

Formula used : \Delta S=\frac{\Delta H_{vap}}{T_b}

Now we have to determine the molar entropy of vaporization for the following compounds.

(a) For Benzene:

Boiling point = 353.1 K

Enthalpy of vaporization = 30.72 kJ/mole = 30720 J/mole

\Delta S=\frac{30720J/mole}{353.1K}=87.00J/K.mole

Thus, this compound is follow the Trouton's rule.

(b) For Toluene:

Boiling point = 383.6 K

Enthalpy of vaporization = 33.18 kJ/mole = 33180 J/mole

\Delta S=\frac{33180J/mole}{383.6K}=86.49J/K.mole

Thus, this compound is follow the Trouton's rule.

(c) For Nonane:

Boiling point = 423.8 K

Enthalpy of vaporization = 37.18 kJ/mole = 37180 J/mole

\Delta S=\frac{37180J/mole}{423.8K}=87.73J/K.mole

Thus, this compound is follow the Trouton's rule.

(d) For Chloroform :

Boiling point = 334.2 K

Enthalpy of vaporization = 29.24 kJ/mole = 29240 J/mole

\Delta S=\frac{29240J/mole}{334.2K}=87.49J/K.mole

Thus, this compound is follow the Trouton's rule.

(e) For Ethanol:

Boiling point = 351.3 K

Enthalpy of vaporization = 38.56 kJ/mole = 38560 J/mole

\Delta S=\frac{38560J/mole}{351.3K}=109.76J/K.mole

Thus, this compound is not follow the Trouton's rule.

(f) For Water:

Boiling point = 373 K

Enthalpy of vaporization = 40.65 kJ/mole = 40650 J/mole

\Delta S=\frac{40650J/mole}{373K}=108.98J/K.mole

Thus, this compound is not follow the Trouton's rule.

8 0
3 years ago
Which would react chemically by forming an ionic bond
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Hope i helped :)</span>
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Electrical current or electrical discharge
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Electric discharge is the consequence of disrupting an isolator (for example, air), thus causing a sudden flow of electricity.
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