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Brrunno [24]
3 years ago
9

What is the atomic number of an element that has 43 protons and 50 neutrons?

Chemistry
1 answer:
zimovet [89]3 years ago
8 0
The atomic number is based on the number of protons, so the atomic number would be 43
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Describe the shapes and relative energies of the SPD & f atomic orbitals
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Explanation:

The shapes and relative energies of the orbitals s,p,d and f orbitals are given by the principal quantum number and the azimuthal quantum number.

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L             Name of orbital                     shape of orbital

0                     s                                         spherical

1                      p                                         dumb-bell

2                     d                                        double dumb-bell

3                      f                                          complex

Principal                        Azimuthal                   Orbital

Quantum                       Quantum                    Designation of

Number (N)                  Number(l)                     Sublevel

       1                                   0                                   1s

       2                                  0                                   2s

                                            1                                   2p

       3                                  0                                   3s

                                            1                                    3p

                                            2                                   3d

      4                                   0                                    4s

                                           1                                      4p

                                           2                                      4d

                                           3                                      4f

Learn more:

Atomic orbitals brainly.com/question/9514863

#learnwithBrainly

6 0
3 years ago
A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu
Jobisdone [24]

Answer:

Work done in this process = 4053 J

Explanation:

Mass of the gas = 0.092 kg

Pressure is constant = 1 atm = 101325 pa

Initial temperature T_{1} = 200 K

Final temperature T_{2} = 200 - 85 = 115 K

Gas constant for nitrogen = 297 \frac{J}{kg k}

When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.

⇒ V ∝ T

⇒ \frac{V_{2} }{V_{1} } = \frac{T_{2} }{T_{1} } ------------ ( 1 )

From ideal gas equation P_{1} V_{1} = m R T_{1} ------ (2)

⇒ 101325 × V_{1} = 0.092 × 297 × 200

⇒ V_{1} = 0.054 m^{3}

This is the volume at initial condition.

From equation 1

⇒ \frac{V_{2} }{0.054} = \frac{200}{115}

⇒ V_{2} = 0.094 m^{3}

This is the volume at final condition.

Thus the work done is given by W = P [V_{2} - V_{1} ]

⇒ W = 101325 × [ 0.094 - 0.054]

⇒ W = 4053 J

This is the work done in that process.

7 0
3 years ago
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