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kondor19780726 [428]
3 years ago
13

What name should be used for the ionic compound Cu(NO3)2

Chemistry
2 answers:
Sergeu [11.5K]3 years ago
6 0
<span>Copper(II) nitrate. Hope i cleared your doubt</span>
devlian [24]3 years ago
4 0

Answer: The name is Copper(II) nitrate.

Explanation: The name of the ionic compounds is written by writing the name of the cation first followed by its oxidation state in round brackets and then the name of the anion is written without any suffix.

Thus the cation copper is written first as calcium followed by the oxidation state as (II) and then the anion which is nitrate.

Thus the name is Copper(II) nitrate.

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The question is in the picture below
Rus_ich [418]

Answer:

\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

\bf{\text{A} \rightarrow 2\text{B}}                  (Δ\text{H}_1)  -----(1)

Since we have 2B, multiply the whole of II. by 2:

\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}       (2Δ\text{H}_2) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is \text{A} \rightarrow 2\text{C} +2\text{D}.

Reversing III. gives us a negative enthalpy change as such:

\bf{2\text{D} \rightarrow \text{E}}                  (-Δ\text{H}_3) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of \text{A} \rightarrow 2\text{C} +\text{E}, which is also the equation of interest.

Adding all three together:

\text{A} \rightarrow 2\text{C}+\text{E}            (\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 })

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

4 0
1 year ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
Please help me asap!
vesna_86 [32]

Answer:

bebe bebe bebe

Explanation:

5 0
3 years ago
¿Qué elemento tiene el mismo número de órbitas que el Hidrógeno? ¿Por qué? ¿Tienen propiedades similares, por qué?
Aliun [14]

What element has the same number of orbits as Hydrogen? Why? Do they have similar properties, why?

Answer:

Helium

Explanation:

Helium has the same number of orbitals as hydrogen because they belong to the same period on the periodic table.

Periods are the horizontal arrangement of elements. Elements in the same period are known to have the same number of electronic shell or orbitals.

In period 1 where we have just Hydrogen and Helium, the number of orbitals is 1.

 

For properties of a specie, elements in the same group which are the vertical arrangement of elements have the same properties. Since both Hydrogen and helium are in different groups, their properties differ.

7 0
2 years ago
So42? draw the molecule by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons. show t
vivado [14]
A molecular structure is a shape of a molecule, a three-dimensional shape or configuration of a molecule that is dependent on the preferred spatial orientation of covalent bonds to atoms having two or more partners. Attached is the diagram for the molecular structure of So42
. 

3 0
3 years ago
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