Answer:
1) 
2) ![\sqrt[3]{-1331}=-11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D%3D-11)
3) Evaluating 
we get 
4) 
5) 
Step-by-step explanation:
1) 
Prime factors of 1225 : 5x5x7x7
Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2
2) ![\sqrt[3]{-1331}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D)
We know that ![\sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B-x%7D%3D-%5Csqrt%5Bn%5D%7Bx%7D%20%5C%20%28%20%5C%20if%20%5C%20n%20%5C%20is%20%5C%20odd%29)
Applying radical rule:
![\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D%5C%5C%3D-%5Csqrt%5B3%5D%7B1331%7D%20%5C%5C%3D-%5Csqrt%5B3%5D%7B11%5Ctimes%5C11%5Ctimes11%7D%5C%5C%3D-%5Csqrt%5B3%5D%7B11%5E3%7D%20%5C%5CUsing%20%5C%20%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx%20%5C%5C%3D-11)
So,
3)
It can be written as:
Evaluating we get
4) 
Put value of x, y and z in equation and solve:
So,
5) 
We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd
So,
Answer:
1/2x plus -2
Step-by-step explanation:
The Multiplication Property of Zero.
It states "the product of any number and zero is zero". Even if there are more than one multiplier - it is still 0.
So 5 x 0 = 0
100 x 0 = 0
41 x 0 x 3 = 0
etc.
Test the choices !
Pick an even number, and see what each choice does to it.
Let's start with, say, 6 .
We'll try each choice, and see which one produces an odd number:
a). 6 to the 2nd power. . . . . . 6 x 6 = 36. That's not an odd number.
b). 6 + 3 = 9 This could be it. 9 is odd. We'll save this one.
c). 3·6 = 18. That's not an odd number.
d). 6/3 = 2. That's not an odd number.
The only one that gave us an odd number is (b).
I think its 201.333333333
