Answer:
Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second
emf = B * l * v
B = flux density ; l = length of the wire ; v = velocity of the conductor
emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts
The emf produced is 0.90 volts.
Step-by-step explanation:
9514 1404 393
Answer:
59) not similar
60)
Step-by-step explanation:
59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.
7:8:12 ≠ 6:7:11
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60) The side length ratios both reduce to 8:7:10, so the triangles are similar.
∆ABC ~ ∆JKL
The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)
Answer:
9600 sq in
Step-by-step explanation:
30 x 20 x 16 = 9600
<span>I can be wrong, but I think that the answer is: To find the values of p, q, r and s, you should start by finding all factor pairs of the leading coefficiant and constant term. </span>