Solve and check: 5 - 6 = -3 k

1 answer:

3 0

$5 - 6 = - 3k \\ - 1 = - 3k \\ \frac{1}{3} = k$
First, we combine the terms on the left side of the equation to simplify the equation. Then we divide both sides by -3. k then equals 1/3.
To check, we plug in our value for k into the original equation:
$5 - 6 = - 3k \\ 5 - 6 = - 3( \frac{1}{3} ) \\ - 1 = - 1$
We found k to be 1/3, so for every instance of k, we plug in 1/3. To simplify, we combine the left side to get -1, and we combine the right side to get -1.
Since -1 = -1, our solution is correct.

You might be interested in

Which of these graphs below represents a function?

Molodets [167]

Answer:

the one you've selected pink, (the one that looks like a U)

Step-by-step explanation:

if you can pass a vertical line through a supposed function and have it only cross once, it's a function.

4 0

3 years ago

Slope intercept of (2,-12) and (5,6)

nlexa [21]

Answer:

The slope of the line is m=6.

The y-intercept is (0,−24).

The equation of the line in the slope-intercept form is y=6x−24.

Step-by-step explanation:

The slope of the line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=2, y1=−12, x2=5, y2=6.

Plug the given values into the formula for the slope: m=(6)−(−12)(5)−(2)=183=6.

Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).

b=−12−(6)⋅(2)=−24.

Finally, the equation of the line can be written in the form y=mx+b.

y=6x−24.

Answer:

The slope of the line is m=6.

The y-intercept is (0,−24).

The equation of the line in the slope-intercept form is y=6x−24.

8 0

2 years ago

Read 2 more answers

Let f(x)=cos(x)x^-2 F’(x)=

kondaur [170]

$f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}$