3 years ago

19x+rx=-37x+w what does x equal

Mathematics

1 answer:

enyata [817]3 years ago

5 0

Factor the left side:

x (19+ r)= -37 + w
x= (-37 + w) / (19 +r)

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3 years ago

Frances gets 6 paychecks in 12 weeks. How many paychecks does she get in 52 weeks?

MA_775_DIABLO [31]

She would get 26

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2 years ago

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3 years ago

Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

2 years ago

Factorise x(6x - 5y) - 4(6x - 5y)^2

Fed [463]

Answer:

(6x-5y)(20y-23x)

Step-by-step explanation:

x(6x - 5y) - 4(6x - 5y)^2

= (6x-5y)(x-4(6x-5y))

= (6x-5y)(x-24x+20y)

= (6x-5y)(20y-23x)

5 0

2 years ago