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11111nata11111 [884]
3 years ago
13

What is the Area of 10cm & 15cm?

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

Answer:

150

Step-by-step explanation:

Area is length times width when you only have 2 #'s.

10×15=150

15×1=15

Add the 0.

150

VashaNatasha [74]3 years ago
6 0

Answer:

150cm

Step-by-step explanation:

The area is base times height 10 times 15 which is 150 cm

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Select the correct answer. If a coin is flipped 10 times, what is the probability that it will show all heads or all tails?
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<span>A). (1/2) The Probability is the same for both heads and tails because there are only two sides.</span>
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Find cos(2*ABC) 100POINTS
juin [17]

Answer:

-\dfrac{7}{25}

Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

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  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

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2 years ago
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Which equation can be used to solve for x in the triangle below?
belka [17]

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<h3>How to Use the Cosines Rule to Solve a Triangle?</h3>

The cosine rule is given as, c = √(a² + b² − 2ab × cos(C))

Given the following:

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  • b = 4.7 cm
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Plug in the values:

x = √(4.0² + 4.7² − 2(4.0)(4.7) × cos(41))

x ≈ 3.1 cm

Learn more about the cosine rule on:

brainly.com/question/23720007

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Given the Arithmetic sequence A1,A2,A3,A4 44, 51, 58, 65 What is the value of A39?
snow_lady [41]
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