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3 years ago

Laboratory aprons or coats should be worn when working with

Physics

2 answers:

laila [671]3 years ago

8 0

Answer:

They should be worn while working with chemicals in labs

Explanation:

Reil [10]3 years ago

6 0

They should be worn while working with chemicals in labs

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Anyone that is really good at physics please message me ! ;(

Lady_Fox [76]

Answer:

Explanation:

5 0

4 years ago

It takes a car 1.75 h to go from mile marker 10 to mile marker 115. What is the average speed of the car? Someone who took this

givi [52]

The distance from mile-mark 10 to mile-mark 115 is (115-10) = 105 miles.

Speed = (distance covered) / (time to cover the distance) .

Speed = (105 miles) / (1.75 hours)

Speed = (105/1.75) (mi/hr)

<em>Speed = 60 mph</em> (B)

3 0

4 years ago

Read 2 more answers

A radio have a wavelength of 0.3m and travels at a speed of 300,000,000 m/s. What is the frequency of this wave?

Ilya [14]

The frequency of the wave is $1\cdot 10^9 Hz$

Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

$c=f \lambda$

where

c is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

For the radio wave in this problem,

$\lambda = 0.3 m$

$c=300,000,000 m/s = 3\cdot 10^8 m/s$

Therefore, the frequency is:

$f=\frac{c}{\lambda}=\frac{3\cdot 10^8}{0.3}=1\cdot 10^9 Hz$

Learn more about waves here:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

4 0

3 years ago

15. An e.mf. of 16 volts is induced in a coil of inductance 4H. The rate of change of current must be:

alex41 [277]

0 64 A/S for surety of

7 0

3 years ago

A satellite of mass 5600 kg orbits the Earth and has a period of 6200 s.

Troyanec [42]

Answer:

(a) Radius of orbit will be $=7.32\times10^6m$

(b) Earth gravitational force will be $=4.18\times 10^4N$

Explanation:

We have given

Mass of the earth, $M=6\times 10^{24}kg$

Mass of the satellite, m = 5600 kg

Radius of earth, $R=6.4\times 10^6m$

Time period T = 6200 sec

We know that $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{6200}=0.00101rad/sec$

Now

(a) We know that $\omega ^2=\frac{GM}{R^3}$

$R^3=\frac{GM}{\omega ^2}$

$R^3=\frac{6.67\times 10^{-11}\times 6\times 10^{24}}{0.00101 ^2}$

$R^3=3.92\times 10^{20}$

Radius of the orbit $R=7.32\times 10^6m$

(b)

Force $F=\frac{GMm}{R^2}=\frac{6.67\times 10^{-11}\times 6\times 10^{24}\times 5600}{(7.32\times 10^6)^2}=4.18\times 10^4N$

(c)

Altitude $h=radius\ of\ orbit-radius\ of\ earth=7.32\times 10^6-6.4\times 10^6=0.92\times 10^6m$

8 0

3 years ago

Laboratory aprons or coats should be worn when working with​

Laboratory aprons or coats should be worn when working with