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Sidana [21]
3 years ago
14

A thin conducing plate 2.3 m on a side is given a total charge of −20.0 µC. (Assume the upward direction is positive.) (a) What

is the electric field (in N/C) 1.0 cm above the plate? (Indicate the direction with the sign of your answer.)
Physics
1 answer:
STALIN [3.7K]3 years ago
4 0

Answer:

The electric field is -2.14\times10^{5}\ N/C

Explanation:

Given that,

Distance = 2.3 m

Charge q= -20.0\ \muC

We need to calculate the electric field

Using formula of electric field

E=\dfrac{\sigma}{2\epsilon_{0}}

Where, \sigma=\dfrac{Q}{A}

Q = charge

A = area

Put the value into the formula

E=\dfrac{Q}{2A\epsilon_{0}}

E=\dfrac{-20.0\times10^{-6}}{2\times2.3\times2.3\times8.85\times10^{-12}}

E=-213599.91\ N/C

E=-2.14\times10^{5}\ N/C

Negative sign shows the direction of the electric field.

The direction of electric field is toward the plates.

Hence, The electric field is -2.14\times10^{5}\ N/C

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