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anyanavicka [17]
3 years ago
11

The student who performed this experiment in the question above wrote the following discussion: "The gas sample is known to cont

ain compounds of only hydrogen and carbon. The measured molecular weight of the flammable gas is closest propane (44.1 g/mole), but lies between propane and butane (58.1 g/mole). I therefore conclude that there is a possibility that the sample is not a pure compound but rather is equal parts propane and butane." This seems qualitatively reasonable except her hypothesis that the gas is a 1:1 mixture is not supported by the data. What gas mixture is suggested by the molecular weight measured in the experiment? Give the percent propane in the mixture in the box provided. Do not enter the percent symbol. Enter your answer with the correct number of significant digits.
Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

What was the experimental measurement of the gas?

Explanation:

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Asap Help!!! I just wanted to know if my answer is correct i am not sure if its not please correct me
Elenna [48]

Answer:

Precipitate

Explanation:

A precipitate is a solid formed from a chemical solution

7 0
2 years ago
Read 2 more answers
A voltaic cell is constructed with two silver-silver chloride electrodes, where the half-reaction is
NemiM [27]
The silver chloride electrode usually functions as a redox electrode where the equilibrium is achieved between silver and its salt (silver chloride).
The half reaction for this electrode is as follow:
<span>AgCl(s)+e−→Ag(s)+Cl−(aq) where:
</span>(s) refers to solid state
(aq) refers to the aqueous state and 
e- is the electron
5 0
3 years ago
Which of the following equations can be used to determine the change in enthalpy of a system? A. `DeltaH_"reaction"=DeltaH_"prod
Nostrana [21]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

Hence, the correct answer is Option D.

6 0
3 years ago
The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.
user100 [1]

Answer:

c    43.38 g

Explanation:

The reaction  between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.  

For the fact that HCl  gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess,  while the limiting reagent should be MnO2 .  

Thus, the theoretical yield of Cl2 will be  60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),  

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% *  60.25 = 43.38 g

5 0
3 years ago
Calculate the mass of 12.3 moles of MgSO4.​
Afina-wow [57]

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

8 0
2 years ago
Read 2 more answers
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