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anyanavicka [17]
3 years ago
11

The student who performed this experiment in the question above wrote the following discussion: "The gas sample is known to cont

ain compounds of only hydrogen and carbon. The measured molecular weight of the flammable gas is closest propane (44.1 g/mole), but lies between propane and butane (58.1 g/mole). I therefore conclude that there is a possibility that the sample is not a pure compound but rather is equal parts propane and butane." This seems qualitatively reasonable except her hypothesis that the gas is a 1:1 mixture is not supported by the data. What gas mixture is suggested by the molecular weight measured in the experiment? Give the percent propane in the mixture in the box provided. Do not enter the percent symbol. Enter your answer with the correct number of significant digits.
Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

What was the experimental measurement of the gas?

Explanation:

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Compare the rates of effusion for carbon monoxide and carbon dioxide gases
Airida [17]
According to Grahams law the rate of effusion of a gas is inversely proportional to the square root of it's molecular weight. The rate of diffusion is the measure of rate at which two gases mix. From this law we can say that for the two gases carbon monoxide and carbon dioxide, the rate of effusion of carbon monoxide is greater than that of carbon dioxide, this is because carbon monoxide is lighter (28 g) compared to carbon dioxide (44 g). 
7 0
3 years ago
Question 2 (0 points)
bazaltina [42]

Answer:

The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}

Put the value into the formula

P(A)=\dfrac{1}{4}

We need to calculate the probability of odd number of the die

Using formula of probability

P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}

Put the value into the formula

P(B)=\dfrac{3}{6}

P(B)=\dfrac{1}{2}

We need to calculate the probability  of spinning red with the spinner or rolling an odd number with the  die

Using formula of probability of two events which is independent

P(A\ and\ B)=P(A)\times P(B)

Put the value into the formula

P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}

P(A\ and\ B)=\dfrac{1}{8}

Hence, The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

5 0
3 years ago
Can someone help out pls
Troyanec [42]

Answer:

1. Acids

2. Its molecular arrangement

3. Very acidic

4. Unsaturated

5. Apple juice

Explanation:

1. Acids have pH less than 7

2. Water molecules have a polar arrangement of the oxygen and hydrogen atoms—one side (hydrogen) has a positive electrical charge and the other side (oxygen) had a negative charge.3. Very acidic

4. Unsaturated solutions are solutions in which the amount of dissolved solute is less than the saturation point of the solvent (at that specific temperature gradient).

5. The lower the pH, the more hydrogen molecules.

4 0
3 years ago
Read 2 more answers
8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8
garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7)  kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0
3 years ago
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-gpiece. How many kilograms of dietary fa
Genrish500 [490]

Answer:  0.14 kg

Explanation:

Gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece

That is 1 piece of candy weighs 22.7 g and contains 7.00 g of dietary fat

Converting the mass in pounds to kg  

1 lb = 0.45 kg = 450 grams    (1kg=1000g)

Number of pieces = \frac{450}{22.7g}=20pieces

1 piece contains = 7 g of dietary fat

Thus 30 pieces would contain =\frac{7}{1}\times 20=140g of dietary fat

1 g = 0.001 kg

Thus 140 grams =\frac{0.001}{1}\times 140=0.14kg

Thus 0.14 kg of dietary fat are in a box containing 1.00 lb of candy.

5 0
3 years ago
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