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anyanavicka [17]
3 years ago
11

The student who performed this experiment in the question above wrote the following discussion: "The gas sample is known to cont

ain compounds of only hydrogen and carbon. The measured molecular weight of the flammable gas is closest propane (44.1 g/mole), but lies between propane and butane (58.1 g/mole). I therefore conclude that there is a possibility that the sample is not a pure compound but rather is equal parts propane and butane." This seems qualitatively reasonable except her hypothesis that the gas is a 1:1 mixture is not supported by the data. What gas mixture is suggested by the molecular weight measured in the experiment? Give the percent propane in the mixture in the box provided. Do not enter the percent symbol. Enter your answer with the correct number of significant digits.
Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

What was the experimental measurement of the gas?

Explanation:

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Anastaziya [24]

Answer:

162.7miles/hr

Explanation:

Given parameters:

Distance covered by the train  = 813.5miles

Time taken  = 5hours

Unknown:

Speed of the train  = ?

Solution:

Speed is a physical quantity.

It is mathematically expressed as;

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So, input parameters and solve;

   Speed  = \frac{813.5}{5}  = 162.7miles/hr

8 0
3 years ago
A 1.0 mole sample of fluorine gas at 25 °C has an average molecular velocity of 415 m/s. What is the total KE of the gas sample?
Mariana [72]

The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

  • KE is the kinetic energy
  • m is the mass
  • v is the velocity

<h3>How to determine the mass of the fluorine gas</h3>
  • Molar mass of fluorine gas = 38 g/mol
  • Mole of fluorine gas = 1 mole
  • Mass of fluorine gas = ?

Mass = mole × molar mass

Mass of fluorine gas = 1 × 38

Mass of fluorine gas = 38 g

<h3>How to determine the KE of the gas sample</h3>
  • Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
  • Velocity (v) = 415 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.038 × 415²

KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

Learn more about energy:

brainly.com/question/10703928

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4 0
2 years ago
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Serga [27]

Answer:

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Explanation:

3 Carbon atoms

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8 0
3 years ago
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inn [45]
Through manipulation of equations, we are able to obtain the equation:

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Then we can transform the equation into:

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Then we are able to plug in the pOH and directly get [OH-]:

[ OH^{-}] = 10^{-6.48}

[ OH^{-}]=3.31* 10^{-7} M
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3 years ago
Which one of these is NOT a sign of chemical change? *
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I think it’s light
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