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elena-s [515]
2 years ago
11

Calcule la formula empírica de la sustancia está compuesta por 18,4% de carbono 21,5% de nitrógeno y 60,1% de potasio

Chemistry
1 answer:
n200080 [17]2 years ago
6 0

Answer:

La fórmula empírica es C₂N₂K₅

Explanation:

La fórmula empírica es la expresión más sencilla para representar un compuesto químico e indica los elementos que están presentes y la proporción mínima en números enteros que hay entre sus átomos. A esta fórmula se le conoce también como “fórmula mínima” .

En otras palabras, la fórmula empírica muestra la proporción entre los átomos de un compuesto químico.

Si supones que tenes 100 gramos del compuesto, los porcentajes en masa indicarán los gramos de cada elemento en esos 100 gramos. Si la sustancia está compuesta por 18,4% de carbono, 21,5% de nitrógeno y 60,1% de potasio, entonce habrá 18,4 g de carbono, 21,5 g de nitrógeno y 60,1 g de potasio

Para la obtención de la fórmula empírica entonces, teniendo en cuenta la masa molecular de cada sustancia, en primer lugar se calcula el número de moles relativos de cada elemento químico:

C: 18.4 g/12 g/mol = 1.5 moles

N: 21.5 g/14 g/mol = 1.5 moles

K: 60.1 g/16 g/mol = 3.75 moles

De esta manera hallas la relación entre el número de moles de los distintos elementos, pero no estará expresada en forma de números enteros y sencillos. Para expresar la relación anterior en forma de números enteros y sencillos, divides el número de moles de cada elemento entre el número de moles menor de todos ellos.

C =  1.5 moles/ 1.5 moles = 1

N =  1.5 moles/ 1.5 moles = 1

K =  3.75 moles/ 1.5 moles = 2.5

Si no se obtiene una relación de números enteros, debes multiplicar por un número sencillo para conseguirlo. En este caso, multiplicando por dos obtienes:

C= 2

N= 2

K= 5

<u><em>La fórmula empírica es C₂N₂K₅</em></u>

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Answer:

10. mol NaOH

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7 0
2 years ago
What is the concentration of a solution which is 2g in 150cm3 in g/dm3
Irina-Kira [14]

Answer:

13.33 g/dm³

Explanation:

Concentration (g/dm³)= mass(g) ÷ volume (dm³)

Now you need to convert 150 cm³ to dm³

1000cm³ = 1 dm³

thus, 150 cm3= 150 ÷ 1000

= 15dm³

and you already have mass in grams

so concentration  = 2 ÷ 0.15

= 13.33 g/dm³ and there you go.. solved ;)

8 0
2 years ago
exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equili
egoroff_w [7]

Answer:

K = 0.2

Explanation:

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The equilibrium constant, K, of the reaction is:

K = [NO₂]² / [N₂O₄]

Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M

as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.

Replacing in K:

K = [0.4M]² / [0.8M]

<h3>K = 0.2</h3>
5 0
3 years ago
A balloon contains 5 L of oxygen at a pressure of 90 kPa. How much oxygen will the balloon contain if the pressure is lowered to
laila [671]
Answer is: volume will be 6,7 L.
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p</span>₁V₁ = p₂V₂.
90 kPa · 5 L = 67 kPa · V₂.
V₂ = 90 kPa · 5 L / 67 kPa.
V₂ = 6,7 L, but same amount of oxygen.


7 0
3 years ago
How many significant figures in 8400
IrinaK [193]

Answer:

there are two significant figures is the number 8400

Explanation:

5 0
2 years ago
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