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1 year ago

What type of intermolecular forces are expected between 4-methylcyclohexanone molecules?

Chemistry

1 answer:

Keith_Richards [23]1 year ago

7 0

The answer is dipole-dipole and dipole-induced dipole forces.

The dipole-induced dipole is a kind of interaction induced by a polar molecule by disturbing the arrangement of electrons.

In methyl cyclohexanone molecules, there is a permanent dipole moment due to dipole moment vectors not canceling.
There is induction of dipole by disturbing the electronic arrangement.
A permanent dipole moment is created in this interaction.
Dipole-dipole interactions are defined as the forces that is formed from the close linkage of permanent or induced dipoles.
These forces are called Van der Waal forces.
Proteins contain a large number of these interactions, which vary considerably in strength.

To learn more about dipole-dipole interactions visit:

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A substance with a define shape and volume is a blank phase of metter

aksik [14]

Definite Shape and Definite Volume is a solid.

NO Definite Shape and Definite Volume is a liquid.

NO Definite Shape and NO Definite Volume is a gas.

4 0

2 years ago

Compounds in a and b were named incorrectly. On a sheet of paper draw the molecule that fits the given description. From the str

krok68 [10]

Answer:

a. 4—ethyl—5—methyloctane

b. 2,2,6—trimethyloctane

Explanation:Please see attachment for explanation

3 0

2 years ago

B. What do you notice about the number of atoms in one mole?

Doss [256]

Answer:

one mole of atom of any element contains6.022×1033 atoms regardless of the type of elements the mass of one mole of an element depend on what that element is and is equal to atom mass of that element in gram

5 0

2 years ago

A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %

kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and $y_{C-6}$ and $y_{N_2}$ are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

$H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol$

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

$Q=-40036+(-672.21)=-40708.21J$

Finally we convert this result to kJ:

$Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ$

Learn more:

6 0

1 year ago

Number of grams of hcl that can react with 0.500 grams of Al(OH)3

vlabodo [156]

Answer:

0.7g of HCl

Explanation:

First, let us write a balanced equation for the reaction between HCl and Al(OH)3.

This is illustrated below:

Al(OH)3 + 3HCl —> AlCl3 + 3H2O

Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:

Molar Mass of Al(OH)3 = 27 + 3(16+1)

= 27 + 3(17) = 27 + 51 = 78g/mol.

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g

Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:

Al(OH)3 + 3HCl —> AlCl3 + 3H2O

From the equation above,

78g of Al(OH)3 reacted with 109.5g of HCl.

Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl

7 0

3 years ago