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3 years ago

Plz hep in the picture below brainliest 98 pionts

Mathematics

2 answers:

AfilCa [17]3 years ago

6 0

The answer is 180. Here is my work:

Ghella [55]3 years ago

3 0

IT IS 180 because 12*15 is one 180 and it cant go over 187.

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(C) A bakery sells 9 types of sandwiches. Here are their calorie amounts: 562.568. 590. 599. 611.621. 623. 641, 938. Which measu

Ludmilka [50]

Answer:

611

Step-by-step explanation:

The mean is 632.9 which is a lot higher than 611, and is actually higher than the penultimate value 632, and if presented as a general single value, it may mislead customers into thinking that the sandwiches have a high calorific value. We don’t know how many sandwiches of different types there are, and there may only be a few with high values. So I would use the median 611 as a typical value for the number of calories.

6 0

3 years ago

Please help me!!!!!!!!!!

PolarNik [594]

Just divide the arc the inscribe angle forms by 2. So 100/2 = 50 = a, and b is 55.

4 0

4 years ago

Read 2 more answers

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

A large cheese pizza costs $7.50. Each additional topping for the pizza costs $1.35. If the total bill for the pizza Sally order

konstantin123 [22]

Answer: She ordered 4 toppings.

Step-by-step explanation:

Given: Total cost of pizza = $ 12.90

Cost of pizza =$7.50

Price per topping = $1.35

Let x = Number of toppings,

Total cost of pizza = (Cost of pizza) + (price per topping) × (Number of topping)

$12.90= 7.50+1.35x\\\\\Rightarrow\ 1.35x=12.90-7.50\\\\\Rightarrow\ 1.35x=5.4\\\\\Rightarrow\ x=\dfrac{5.4}{1.35}\\\\\Rightarrow\ x=\dfrac{540}{135}=4$

hence, she ordered 4 toppings.

5 0

3 years ago

Given any two arcs, the larger of the arcs is always called a minor arcTrueFalse

GrogVix [38]

When we have two arcs in a circle, one larger and one smaller, one will be called the minor arc and the other the minor arc.

The name of the arc depends on its size, for example, given the following green and yellow arcs, the green, which is smaller, will be the minor arc:

Therefore, the larger arc is always called Major arc, not minor arc.

The statement is False.

Answer: False

4 0

1 year ago