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arsen [322]
4 years ago
5

The least penetrating form of radiation is

Physics
2 answers:
pentagon [3]4 years ago
8 0

Answer:

Answer:

1. emits energy when it decays

2. 0

3. helium nucleus

The least penetrating form of radiation: 4. alpha radiation

5. increases by 1

Explanation:

kondaur [170]4 years ago
6 0

Answer: alpha radiation

Explanation:

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4 years ago
What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass
Anvisha [2.4K]

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz

The frequency of the simple pendulum is given as;

F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m

Thus, the length of the simple pendulum is 0.25 m.

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3 years ago
Make I the subject<br> E=VIt
slava [35]

To Make I the subject you need to get it by itself. To do this divide both sides by V and t:

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