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3 years ago

As you add or remove neutrons from the nucleus, isotopes are formed

1 answer:

7 0

That's true: isotopes are chemical elements with same atomic number (i.e. same number of protons) but different mass number (i.e. different number of protons+neutrons, so if the number of protons is the same, the number of neutrons should be different).
For instance, hydrogen has three different isotopes:
- protium, with only one proton in the nucleus
- deuterium, with one proton and one neutron
- tritium, with one proton and two neutrons

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A car traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. What was its acceleration? Round your answe

Contact [7]

Answer:

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

$34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s$

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2$

Acceleration is 51.94 ft/s²

$v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s$

Final velocity at this time is 257.63 ft/s

5 0

3 years ago

Use tug of war to explain balanced and unbalanced forces

Ghella [55]

<em>in tug of war if you are balanced, it would be a tie. But, say its unbalanced it would be one side wins. It all depends on the amount of people and whos stronger.</em>

4 0

3 years ago

Help with the two questions above? Correct answers?

LenKa [72]

(6) first choice: the frequency appears higher and wavelength is shorter.

The car approaches a stationary observer and so the sound will appear to have shorter wavelength. This creates an effect of its siren to sound with higher frequency than it would do if both were stationary.

(7) The Doppler formula for frequency in the case of a stationary observer and source approaching it is as follows:

$f_O = \frac{v}{v-v_s}\cdot f= \frac{343\frac{m}{s}}{(343-25)\frac{m}{s}}\cdot 400Hz \approx 431Hz$

The wavelength is then

$\lambda = \frac{343\frac{m}{s}}{431Hz}\approx 0.80 m$

The third choice "0.80m; 431Hz" is correct

7 0

3 years ago

How far must the point charges q1 = +7.22 µc and q2 = -32.5 µc be separated for the electric potential energy of the system to b

Alik [6]

The formula that we wil be using is the formula for two charges q and Q separated by a distance r which is: U = kQq/r
Where:
U = electric potential,
Q and q = point charges, and
r = the distance between the point charges.
So we are looking for 'r', rearranging the formula would give us:
U*r = kQq
r = kQq/U -> this will be the formula that we will be using.
r = (9 x 10^9)*(7.22 x 10^-6)*(-32.5 x 10^-6) / -117
r = .01805 m

8 0

4 years ago

People in a community are interested in constructing a hydroelectric dam in

kenny6666 [7]

Answer:

i think it is d

Explanation:

sorry if im wrong

5 0

3 years ago