The answer is D because i'm in the same studies right now.
Answer:
0.084 kg
Explanation:
I = 0.80 N-s (East wards) = 0.80 i N-s
u = 3.8 m/s = - 3.8 i m/s
v = 5.7 m/s = 5.7 i m/s
Let m be the mass of bat.
I = m (v - u)
0.8 i = m ( 5.7 i + 3.8 i)
0.8 i = m x 9.5 i
m = 0.084 kg
The average current density in the wire is given by:

where I is the current intensity and A is the cross-sectional area of the wire.
The cross-sectional area of the wire is given by:

where r is the radius of the wire. In this problem,
, so the cross-sectional area is

and the average current density is

The sun . plz give me a nice thank you