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3 years ago

One ball is dropped vertically from a window. At the same instant, a second ball is thrown horizontally from the same window.

Physics

1 answer:

geniusboy [140]3 years ago

7 0

Answer:

The second ball

Explanation:

Both balls are under the effect of gravity, accelerating with exactly the same value. The first ball is dropped, therefore its initial velocity is zero. Since the second ball has horizontal and vertical velocity components, its initial velocity is given by:

$v=\sqrt{v_x^2+v_y^2}$

The vertical component is zero, however, it has a horizontal velocity, so its initial speed is not zero, therefore the secong ball has the greater speed at ground level.

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What is the net work doneon the object over the distance shown?

GuDViN [60]

$A)F_0d$

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

Area:

$\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}$ $\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}$

$\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}$

therefore, the answer is

$A)F_0d$

I hope this helps you

4 0

1 year ago

Cientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.

scZoUnD [109]

Answer:

A few of the positive particles aimed at a gold foil seemed to bounce back.

Explanation:

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3 years ago

Can someone answer this for me? it’s due today and i need it done asap! i will give brainlist!!

Setler79 [48]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

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serious [3.7K]

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2 years ago

A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?

Ket [755]

The energy carried by a single photon of frequency f is given by:
$E=hf$
where $h=6.6 \cdot 10^{-34} m^2 kg s^{-1}$ is the Planck constant. In our problem, the frequency of the photon is $f=7.15 \cdot 10^{14}Hz$ , and by using these numbers we can find the energy of the photon:
$E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J$

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3 years ago