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Tju [1.3M]
4 years ago
9

One ball is dropped vertically from a window. At the same instant, a second ball is thrown horizontally from the same window.

Physics
1 answer:
geniusboy [140]4 years ago
7 0

Answer:

The second ball

Explanation:

Both balls are under the effect of gravity, accelerating with exactly the same value. The first ball is dropped, therefore its initial velocity is zero. Since the second ball has horizontal and vertical velocity components, its initial velocity is given by:

v=\sqrt{v_x^2+v_y^2}

The vertical component is zero, however, it has a horizontal velocity, so its initial speed is not zero, therefore the secong ball has the greater speed at ground level.

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Can some answer 7 a and b please
pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

V_{f} =1.7 m/s

Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

4 0
4 years ago
H is a chemical H2 is a chemical
irina1246 [14]
A because it is a formula for h*2
5 0
3 years ago
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An electromagnetic wave traveling through a vacuum has a wavelength of 1.5 × 10-1 meter. What is the period of this wave?
LiRa [457]

Answer: (1) 5.0 x 10^ -10 s

Explanation:

1.5 x 10^-1 m / 3 x 10^8 = .5 x 10^-9

= 5 x 10^-10

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What is the main difference between a gas and a plasma?
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Gases are not ionized while plasma is.

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A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The
solniwko [45]
We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s² 
d = ut + 1/2 at²
6.0 = 0 + (1/2 × 9.80 t²) 
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 = 1.106 sec
Horizontal velocity = Vh = Dh/t
  = 24.0 /1.106 s
  = 21.69 m/s
The ball was thrown at a speed of 21.69 m/s
5 0
4 years ago
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