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Tema [17]
3 years ago
6

A single, non-constant force acts in the x direction on an object of mass m that is constrained to move along the x-axis. As a r

esult the object\'s position as a function of time is:x(t)=P+Qt+Rt^3How much work is done by this force from t = 0 s to final time T? Express your answer in terms of P, Q, R, m, and T.
Physics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

Work done is given as

W = \frac{1}{2}m(2Q + 3RT^2)(3RT^2)

Explanation:

As we know that the position of object is given as

x(t) = P + Qt + Rt^3

now we know that rate of change in position of object is known as velocity

so we have

v = \frac{dx}{dt}

v = Q + 3Rt^2

now we have

initial speed at t = 0

v_i = Q

at t = T final speed is given as

v_f = Q + 3RT^2

now work done is change in kinetic energy

W = \frac{1}{2}m(v_f^2 - v_i^2)

W = \frac{1}{2}m[(Q + 3RT^2)^2 - Q^2]

W = \frac{1}{2}m(2Q + 3RT^2)(3RT^2)

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NikAS [45]

Answer:

A)  350 N

B)  58.33 N

C)  35 kg

D)  35 kg

Explanation:

If we use that g = 10 m/s^2, then the acceleration of gravity on the Moon will be 10/6 m/s^2 = 5/3 m/s*2

The weight of the object on Earth is given by:

Weight = mass * g = 35 * 10 = 350 N

The weight of the object on the Moon:

Weight = mass * gmoon = 35 * 5/3 = 58.33 N

The mass of the object on Earth is 35 kg

The mass of the object on the Moon is exactly the same as on the Earth (35 kg) since the mass is a quantity inherent to the object and not to its location.

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Disorder in the universe increases because
Veronika [31]
I think the answer would be c
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Why is it important to consider the experimental error in all the empirical results presented?
irinina [24]

Answer:

It is very important because scientists, especially the ones with empirical experiments and results, are prone to error and the empirical data is in need to be under strict observation done not only by many scientists but also by expermiented ones. This guards everybody to change the parameters suddenly which can affect the real results of an experiment 

Explanation:

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E14. A ball rolls off a table with a horizontal velocity of 5 m/s. If
Shkiper50 [21]

a) Vertical velocity: 5.9 m/s

b) Horizontal velocity: 5 m/s

Explanation:

a)

The motion of the ball is the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction)

- A uniformly accelerated motion (constant acceleration) along the vertical direction

Here we want to find the vertical component of the ball's velocity. This can be done by using the suvat equation for the vertical motion:

v_y = u_y +gt

where:

v_y is the vertical velocity at time t

u_y=0 is the initial vertical velocity (zero because the ball has been thrown horizontally)

g=10 m/s^2 is the acceleration of gravity (here we take downward as positive direction)

Substituting t = 0.6 s, which is the total time of flight, we find the vertical velocity of the ball just before it hits the ground:

v_y=0+(9.8)(0.6)=5.9 m/s

b)

The motion along the vertical direction is an accelerated motion, because there is a force (the force of gravity) acting on the ball and that it causes an acceleration in the ball.

However, there are no forces acting in the horizontal direction on the ball (if we neglect the air resistance): this means that the acceleration of the ball in the horizontal direction is zero.

As a consequence, this also means that the horizontal component of the ball's velocity is constant during the motion.

Since the ball was thrown from the table with an initial horizontal velocity of 5 m/s, this means that the horizontal velocity of the ball just before it hits the floor is still

v_x =  5 m/s

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