Answer:
9] V = D ÷ T
Take any distance value from the graph and its relevant time.
V = 4 ÷ 2
V = 2 m/s
[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]
10] Take the distance value and its time for the highest peak of B.
V = 20 ÷ 2
V = 10 m/s
can you have all of them as possibilities ???
Answer
given,
at time t = 10 s moving from left to right speed of particle = 5 m/s
at t = 20 s moving from right to left speed of particle is = 8 m/s
a) acceleration


a = -1.3 m/s²
b) using equation of motion
v = u + at
5 = u - 1.3 × 10
u = 5 + 13
u = 18 m/s
c) v = u + at
0 = 18 - 1.3t

t = 13.85 s