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Marysya12 [62]
2 years ago
11

Writing an Argument About Galetown’s Severe Storms Note: If you do not have access to Amplify Science at home, your teacher will

provide you with an alternate way to complete this homework. In your final report to the citizens of Galetown, you will discuss the three claims and explain how all three factors can contribute to severe storms. Then, you will predict if the storms will always be severe. What caused Galetown to have more severe rainstorms this summer than in previous years?
Claim 1: The lake that was built near Galetown caused it to have more severe rainstorms.

Claim 2: Warmer weather caused Galetown to have more severe rainstorms.

Claim 3: Stronger winds caused Galetown to have more severe rainstorms.

Be sure to use some of the vocabulary words you have learned in both of your writing assignments: Word Bank air parcel, cloud,condensation, energy, evaporation, temperature, transfer, troposphere, water vapor, weather, wind   

Recall from the previous activity which claims you think are best supported by evidence. Use these claims to explain what is happening in Galetown. You can use the data table and the words listed in the word bank above to help you with your report that answers the question: What caused Galetown to have more severe rainstorms this summer than in previous years? Press NEXT to move on to the second part of the written report. Write a 3-5 paragraph argumented essay ​

Physics
1 answer:
jarptica [38.1K]2 years ago
4 0

The claim that can be deduced is that B. Warmer weather caused Galetown to have more severe rainstorms.

<h3>What is a claim?</h3>

It should be noted that a claim simply means the stance of an author in a literary work.

In this case, the claim is that warmer weather caused Galetown to have more severe rainstorms.

When the temperature of an air parcel begins higher, this will make it rise higher in the troposphere before the temperature of the air parcel and surrounding air are equal.

Learn more about claim on:

brainly.com/question/2748145

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Parallel rays of monochromatic light with wavelength 571nm illuminate two identical slits and produce an interference pattern on
Natasha2012 [34]

Answer:

8.8\times 10^{-6} W/m^2

Explanation:

We are given that

Wavelength,\lambda=571 nm=571\times 10^{-9} m

1 nm=10^{-9} m

R=75 cm=\frac{75}{100}=0.75 m

1 m=100 cm

d=0.640 mm=0.64\times 10^{-3} m

1 mm=10^{-3} m

a=0.434 mm=0.434\times 10^{-3} m

y=0.830 mm=0.830\times 10^{-3} m

I_0=5.00\times 10^{-4}W/m^2

tan\theta=\frac{y}{R}

\theta=\frac{0.830\times 10^{-3}}{0.75\times 10^{-2}}

\theta=1.1\times 10^{-3}rad

tan\theta\approx \theta

Because \theta is small.

\phi=\frac{2\pi dsin\theta}{\lambda}

\sin\theta\approx \theta,

Therefore

\phi=\frac{2\times\pi\times 0.64\times 10^{-3}\times 1.1\times 10^{-3}}{571\times 10^{-9}}

\phi=7.74 rad

\beta=\frac{2\pi a\theta}{\lambda}

\beta=5.3 rad

I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2

I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2

I=8.8\times 10^{-6} W/m^2

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

f=12GHz=12\cdot 10^9 Hz is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

So the wavelength of the beam is

\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

y=\frac{m\lambda D}{a}

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So the area is

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And since the power is

P=100 kW = 1\cdot 10^5 W

The average intensity is

I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2

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