Answer:
Explanation:
Given
Velocity = 388m/s
Height S = 2.89m
Required
Time
Using the equation of motion
S =ut+1/2gt²
2.89 = 388t+1/2(9.8)t²
2.89 = 388t+4.9t²
Rearrange
4.9t²+388t-2.89 =0
Factorize
t = -388±√388²-4(4.9)(2.89)/2(4.9)
t= -388±√(388²-56.644)/9.8
t = -388±387.93/9.8
t =0.073/9.8
t = 0.00744 seconds
Answer:
113.85 m
Explanation:
When the car is on the pavement:
v₀ = 0 m/s
a = 5.75 m/s²
t = 4.4 s
Find: Δx and v
Δx = v₀ t + ½ at²
Δx = (0 m/s) (4.4 s) + ½ (5.75 m/s²) (4.4 s)²
Δx = 55.66 m
v = at + v₀
v = (5.75 m/s²) (4.4 s) + 0 m/s
v = 25.3 m/s
When the car is in the mud:
v₀ = 25.3 m/s
v = 0 m/s
a = -5.5 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (25.3 m/s)² + 2 (-5.5 m/s²) Δx
Δx = 58.19 m
The total displacement is therefore:
55.66 m + 58.19 m = 113.85 m
A. Velocity///////////////////
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