Answer:
5a. 4w+24≤100
5b. Dimensions=31ft x 19 ft
Area = 589ft²
Step-by-step explanation:
l=w+12
p=2l+2w
p=2(w+12)+2w
p=2w+24+2w
p=4w+24
The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:
4w+24≤100
For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)
100=4w+24
4w=76
w=19ft
l=w+12
l=19+12
l=31ft
The dimensions are 31ft x 19ft.
Area=lw
=31*19
=589ft²
Step-by-step explanation:
Since SP=TR, the differnce of PR and ST 24-15 divided by 2 is the length of PD (4.5)
Try to understand the rest from the attached picture
What is the mode and median of 1,2,1,3,3,5,3,4,5,4,3,2,5,3,1.
tankabanditka [31]
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