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SCORPION-xisa [38]
3 years ago
13

8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?

Physics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

q_1=q_2=+1C are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N

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A bullet with a mass of 5.00 x 10^-3 kg is loaded into a gun. The loaded gun has a mass of 0.52 kg. The bullet is fired, causing
beks73 [17]
For the answer to the question above,
 220 m/s 
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4 years ago
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3 years ago
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TiliK225 [7]

Answer:

Only 9% weaker

Explanation:

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irga5000 [103]

Answer:

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Explanation:

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