Answer:
(a) 12210 Ω
(b) 9.92 Ω
Explanation:
From Electricity,
(a)
When resistors are connected in series, the total resistance is the sum of the individual resistance.
From the question,
Rt = R1 + R2 + R3................................. R37 ....................... Equation 1
Where Rt = Total resistance of combined resistance, R1 = resistance of the first resistor, R2 = Resistance of the second resistor .......... and so on up to the 37th resistor.
Note: Since The resistor are identical.
Rt = n(R) ..................... Equation 2
Where n = number of resistor, R = resistance of each resistor.
Given: n = 37, R = 330 Ω
Substitute into equation 2
Rt = 37(330)
Rt = 12210 Ω
(b)
For parallel connection,
Rt = R/n...................... Equation 2
Given: R = 330 Ω, n = 37
Substitute into equation 2
Rt = 330/37
Rt = 8.92 Ω
Hence the resistance when connected in parallel = 9.92 Ω
Answer:
Explanation:
a) To get the resistivity ρ at 50 Celsius, given the resitstivity at 20 Celsisus, use:
ρ = ρo(1 + α(T - To))
where To = 20 Celsius
b) Knowing the resistivity at 50 Celsius, and the (uniform) electric field E, you can determine the current density J using:
E = ρJ
(which is actually a density-averaged version of V = IR)
c) Assuming the current is uniform (which is should be in a uniform electric field and constant-diameter wire), the current i can be calculated using:
J = i/A --> i = JA
where A is the cross-sectional area of the wire (given by πr2); make sure to convert the given diameter to a radius, and the radius to base units
d) Since the electric field is given in volts per meter, and you have two meters of length in the wire, you can determine directly from that how many volts difference you need at the ends of the wire to get 0.2 volts per meter.
0.2 = V/d
with d = 2 m. This corresponds to a uniform electric field being related to voltage by V = Ed, where d is distance along the field line.
Properties. Each family has it's own properties, features, and even things like color, malleability, or conductivity.
I already said it but its reactivity
