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mrs_skeptik [129]
2 years ago
9

A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mou

se?
Physics
2 answers:
valina [46]2 years ago
6 0

Answer:

<h2>3.39 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.4 \times  {2.2}^{2}  \\  = 0.7 \times 4.84 \\  = 3.388 \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>3.39 J</h3>

Hope this helps you

Semmy [17]2 years ago
6 0

Answer:

im not sure

Explanation:

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Help me please to do those problems...
Stells [14]

Keeping in mind that:

- Distance is the length of the total path covered by the person, regardless of the directions of the different parts of motion

- Displacement is just the distance in a straight line between the final point and the initial point

Let's apply these concepts to solve the different parts of the problem:

1. 120 m, 80 m west

The total distance is the sum of the length of the different paths:

distance = 100 + 20 = 120 m

To find the displacement, we need to find the distance between the starting point and the ending point. Assuming the starting point as

x = 0

Michelle moved 100 m westward  and 20 m eastward, so the ending point is at

ending point = 100 - 20 = 80 m (westward)

So, the displacement is

displacement = 80 - 0 = 80 m (west)

2. 6400 m, 0

The distance is equal to the length of the track multiplied by the number of laps, so:

distance = 1600 \cdot 4 = 6400 m

The track is circular, and the runner completes exactly 4 laps: it means that at the end of the motion, the runner is at her starting point. So ending point and starting point coincide, and so the displacement

displacement = ending point - starting point = 0

3. 40 m; 10 m forward

The total distance is just the sum of the lengths of the different parts of the motion, so:

distance = 20 + 5 + 10 + 5 = 40 m

The find the displacement, we need to assign signs to every direction:

Forward --> positive along the forward-backward direction

Backard --> negative along the forward-backward direction

Right --> positive direction along the right-left direction

Left --> negative direction along the right-left direction

Along the forward-backward direction, the displacement is:

20 m forward and 10 m backward, so 20 - 10 = 10 (forward)

Along the left right direction, the displacement is:

5 m right and 5 m left, so 5 - 5 = 0

So the net displacement is 10 m (forward)

4. 16 km; 4 km south

Again, t total distance is the sum of the lengths of the different parts of the motion, so:

distance = 2 + 4 + 6 + 4 = 16 km

To find the displacement, we assign signs to every direction:

North --> positive along the north-south direction

south --> negative along the north-south direction

east --> positive direction along the east-west direction

west --> negative direction along the east-west direction

Along the north-south direction, the displacement is:

2 km north and 6 km south, so 2 - 6 = -4 km (4 km south)

Along the east-west direction, the displacement is:

4 km east and 4 km west, so 4 - 4 = 0

So the net displacement is 4 km south

5. 37.7 m; 24 m

The distance covered by the skater is the length of half circumference, so given the radius

r = 12 m

The distance is

distance= \pi r = \pi \cdot (12)=37.7 m

The displacement is the distance in a straight line between the ending position and the starting position. Since the skater ends her motion halfway around the circle, the distance between the initial and final point is equal to the diameter of the circle (two times the radius). So,

displacement = 2r = 2 \cdot 12 = 24 m

3 0
3 years ago
What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?
iogann1982 [59]

The longest wavelength of radiation used to break carbon-carbon bonds is 344 nm.

<u>Explanation:</u>

The longest wavelength of radiation can also be stated as the minimum radiation frequency required to cut carbon-carbon bond should be equal to the threshold energy of the carbon-carbon bonds.

The threshold energy will be equal to the binding energy of the carbon-carbon bonds. As it is known that carbon-carbon bonds exhibit a binding energy of 348 kJ/mole, the threshold energy to break it, is determined as followed.

First, we have to convert the energy from kJ/mol to J, i.e., energy for the carbon-carbon molecules,

\text { Energy } = \frac{348 \mathrm{KJ} / \mathrm{mol}}{6.023 \times 10^{23} \text { photons }} \times 1 \text { mole } \times 1000 = 57.77 \times 10^{-20} = 5.78 \times 10^{-19} J

As,

         E=h v=\frac{h c}{\lambda}

So,

\lambda=\frac{h c}{E}=\frac{6.626 \times 10^{-34} \times 3 * 10^{8}}{5.78 \times 10^{-19}}=3.44 \times 10^{-7}

Thus, \lambda=344 \mathrm{nm} is the longest wavelength of radiation used to break carbon-carbon bonds.

5 0
3 years ago
What are the chances that radio transmissions from Earth or messages sent on distant space probes will ever be received by livin
spin [16.1K]

Answer:

<u>Very low</u>

<u>Explanation:</u>

It is fair to say to a reasonable extent that there are very low chances that radio transmissions from Earth or messages sent on distant space probes will ever be received by living beings .

Bear in mind that for years some scientists have believed without any substantial evidence that there are other living beings in distant space.

4 0
3 years ago
When gravitational field lines get farther apart, the gravitational field _________.
kupik [55]
<span>b. becomes weaker            
try this           </span>
3 0
3 years ago
When a falling object reaches terminal velocity, the net force acting on it is
dexar [7]
Pretty sure that it is 0.
3 0
3 years ago
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