For the answer to the question above,
220 m/s
<span>mass of the bullet * velocity of the bullet = mass of the gun * velocity of the gun </span>
<span>0.005 kg * v = 0.52 kg * 2.1 m/s </span>
<span>-> v = (0.52kg * 2.1 m/s) / 0.005 kg = 218.4 m/s
</span>I hope my answer helped you. Have a nice day!
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PCBs were found in greater concentrations in lakes where more salmon spawned.
Answer:
The thrust of the jet engine is 4188.81 N.
Explanation:
Given that,
Speed = 260 m/s
Rate in air= 53.3 kg/s
Rate of fuel = 3.63 kg/s
Relative speed = 317 m/s
We need to calculate the rate of mass change in the rocket
Using formula of rate of mass

Put the value into the formula


We need to calculate the thrust of the jet engine
Using formula of thrust

Put the value into the formula


Hence, The thrust of the jet engine is 4188.81 N.
Answer:
Explanation:
For image formation in objective lens
object distance u = 14 +1 = 15 mm
focal length f = 14 mm .
image distance v = ?
lens formula

Putting the values

v = 210 mm .
B )
magnification = v / u
= 210 / 15
= 14
size of image = 14 x 1.1 mm
= 15.4 mm
= 15 mm approx
C )
For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .
21 mm is the answer .
D )
overall magnification =

D = 25 cm , f_e = focal length of eye piece
= 14 x 250 / 21
= 166.67
= 170 ( in two significant figures )