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Alenkinab [10]
3 years ago
5

PLEASE HELP! 15 POINTS TO BRAINLIEST!!!

Mathematics
1 answer:
Semenov [28]3 years ago
5 0

first one no second one no third one no frouth no fifth yes last one no

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HURRY<br> What is the volume of this rectangles prism??
kotykmax [81]

The answer is c 400 because 10 times 5 is 50 time 8 equall 400

Step-by-step explanation:

8 0
3 years ago
Write the product in standard form (2x + 5) ^2
Iteru [2.4K]

Answer:

4x^2+20x+25

Step-by-step explanation:

(2x+5)^2 = (2x+5) (2x+5)

Using the foil method : 2x(2x) = 4x^2

(2x) (5) = 10x

(2x) (5) = 10x

5 (5) = 25

Combine like terms

4 0
3 years ago
Which one are correct?
Nesterboy [21]
B and d are correct
8 0
2 years ago
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi
stealth61 [152]
Applying our power rule gets us our first derivative,

\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}

simplifying a little bit,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

looking for critical points,

\rm 0=2x^{-2/3}+4x^{1/3}

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

0=2x^{-2/3}\left(1+2x\right)

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

and take our second derivative.

\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}

Looking for inflection points,

\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}

Again, pulling out the smaller power of x, and fractional part,

\rm 0=-\frac43x^{-5/3}\left(1-x\right)

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
8 0
3 years ago
What is the answer of this question plzzzzzzzzzzz say fast​
Softa [21]

Answer:

1=3=70^{0} \\2=4=5=110^{0}

Step-by-step explanation:

Given angle is 110°

Now,

4=2\,\,and\,\,4=5\,\,;[vertical\,\,angle\,\,and\,\,corresponding\,\,angle\,\,respectively ]

From the figure,

4=110^{0}\,\,;[alternate\,\,angle]

So,\,\,2=5=110^{0}

And, as 1,2,3,4 are vertical angles and 2 = 4 = 110°

1 = 3 = 180° - 110° = 70°

Hope you have understood this.....      

ask me if you have any confusion.....      

if you liked it pls mark it as the brainliest

7 0
2 years ago
Read 2 more answers
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