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2 years ago

Help me please ASAP!!

Mathematics

1 answer:

Mice21 [21]2 years ago

4 0

Choice D is true. It is just another way to write the given function.

To confirm choices A through C, replace x as follows and do the math:

For A, let x = -3. Does it really yield -11?

For B, let x = 0. Does it really yield 5?

For C, let x = 1/2. Does it really yield 4?

Take it from here.

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Timothy read 3,876 pages this school year. Amelia read 3,768 pages. Who read more pages this school year? E

12345 [234]

Answer:

Timothy

Step-by-step explanation:

Timothy because he read 3,876 pages this year.

8 0

2 years ago

. In April, it rained 1/4 of an inch on 15 different days. How many inches of rain fell

notka56 [123]

Answer:

3.75, or $\frac{15}{4}$ inches of rain during the 15 days of April.

Step-by-step explanation:

All you have to do is add $\frac{1}{4}$ 15 times to get that number.

$\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ = 3.75

You can also do 15 times $\frac{1}{4}$ , which will result in the same thing.

#teamtrees #WAP (Water And Plant)

5 0

2 years ago

I was wondering what to pick for my next subjects i just did math and science

34kurt

Answer:

Spanish
Some schools have karate
Technology/Programming

<h2><em><u>Could I please have BRAINLIEST?</u></em></h2>

8 0

2 years ago

Read 2 more answers

If you solve this, you are a critical thinker:

jolli1 [7]

Answer:

8 children

This is because if he has one son, then every daughter has one brother. Therefore, if he has four sons, each of his daughters have four brothers.

6 0

2 years ago

Read 2 more answers

On average 83.1% of welds performed by a particular welder are defective. if, in one day, the welder creates three welds. what i

Nuetrik [128]

Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.

Using the binomial distribution, we want all three to be defective.
$P(X = 3) = \binom{3}{3}(p)^{3}{q}^{3 - 3}$
$P(X = 3) = \binom{3}{3}(0.831)^{3}(1)$
$P(X = 3) = (0.831)^{3} \approx 0.573856191$

4 0

2 years ago