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3 years ago

Which is the correct identity for cos(π/2-θ) ? A. cos θ B. sin θ C. sec θ D. csc θ

Mathematics

2 answers:

icang [17]3 years ago

7 0

I believe the answer is D. I’m terribly sorry if I got it wrong

ella [17]3 years ago

6 0

Answer:

B. sin

Step-by-step explanation:

sin A is equivalent to cos(pi/2-a)

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Miranda enlarged a picture twice as shown below, each time using a scale factor of 3. Which statements apply to the enlargements

stepladder [879]

Answer:

-The area of the second enlargement is 1,944 square inches

-The area of the second enlargement is (3 squared) squared times the original area.

-The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

The complete question is

Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.

A rectangle with length 6 inches and width 4 inches is enlarged twice.

Which statements apply to the enlargements? Select three options.

-The area of the first enlargement is 72 square inches.

-The area of the second enlargement is 1,944 square inches.

-The area of the second enlargement is (3 squared) squared times the original area.

-The area of the second enlargement is 3 times the area of the first enlargement.

-The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor.

Verify each statement

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

First enlargement

Multiply the original dimensions by a scale factor of 3

$Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches$

The area of the first enlargement is

$18(12)=216\ in^2$

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

$Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches$

The area of the second enlargement is

$54(36)=1,944\ in^2$

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is $24\ in^2$

The area of the second enlargement is $1,944\ in^2$

$[(3^2)]^2(24)=1,944\ in^2$

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

$3(216)=648\ in^2$

$648\ in^2 \neq 1,944\ in^2$

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

$\frac{216}{24}=9$

8 0

3 years ago

The 22 students in Mr. Byers 6th grade class each donated $5.00 for Mr. Byers' end of year gift. When Jessica went to purchase t

Advocard [28]

Answer:

$140.00

Step-by-step explanation:

22 students x $5.00 + $30

22 x $5.00 = $110.00

$110.00 + $30.00 = $140.00

7 0

3 years ago

Read 2 more answers

How do I answer this question?

Thepotemich [5.8K]

Answer:

The total cost for 8 skiers=316 dollars

Step-by-step explanation:

Given that the expression 15n+12n+100 represents the total cost in dollars for skis,boots and a lesson for n skiers.

To simplify the given expression :

15n+12n+100=27n+100

27n=-100

Therefore $n=\frac{-100}{27}$

Now to find the total cost for 8 skiers.

The total cost for 8 skiers can be written as below

Put n=8 in the given expression 15n+12n+100

15(8)+12(8)+100

=120+96+100

=316

Therefore the total cost for 8 skiers is 316 dollars

The total cost for 8 skiers=316 dollars

4 0

3 years ago

12345 what is the answer if you multiply 1x2x3x4x5 and do the same with subtraction, addition and devision, in that order. Then

Alexandra [31]

Well, we just need to perform the operations:

Multiplication: $1\cdot 2 \cdot 3 \cdot 4 \cdot 5 = 120$
Subtraction: $1-2-3-4-5 = -13$
Addition: $1+2+3+4+5 = 15$
Division: $1 \div 2 \div 3 \div 4 \div 5 = \frac{1}{120}$

So, if you add all the numbers together you get

$120-13+15+\dfrac{1}{120} = 122 + \dfrac{1}{120}$

Or, if you prefer,

$\dfrac{1681}{120}$

8 0

3 years ago

HELP IM FAILING IF HELP U WILL GET 8 POINTS <3 AND HELP ME

algol [13]

The area of the red part is greater than the area of the blue part.

3 0

3 years ago

Read 2 more answers