All categories

3 years ago

-1-4= 5-3x+4x Please help me! This is kind of confusing, and I don't really understand.

Mathematics

2 answers:

amid [387]3 years ago

8 0

$-1-4= 5-3x+4x\\
-5=5+x\\
x=-10$

Oliga [24]3 years ago

4 0

-1-4=5-3x+4x
3x-4x=5+1+4
-x=10
x=-10
HOPE I HELPED!!!

You might be interested in

How many lines of symmetry does this shape have? Information Answer options with 5 options A. 0 B. 1 C. 2 D. 3 E. 4

Darina [25.2K]

Answer:

D.3? you never showed us the picture

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the value of x.

slavikrds [6]

Answer:

$x=11$

Step-by-step explanation:

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

In this problem

$(x+5)=\frac{1}{2}(3x-1)$

solve for x

Multiply by 2 both sides

$2x+10=3x-1$

subtract 2x both sides

$10=3x-1-2x$

$10=x-1$

Adds 1 both sides

$x=11$

3 0

3 years ago

What is the slope for y=-5x-6

olga_2 [115]

Answer:

-5 is the slope and -6 is the y intercept

Step-by-step explanation:

This is in the form

y =mx+b where m is the slope and b is the y intercept

y = -5x -6

-5 is the slope and -6 is the y intercept

3 0

3 years ago

10 points need help asap

alexandr402 [8]

Answer:

Cross section is the term name given to the front of any prism. SO, they are only found in a prism. They are recognized as the side/face that appears twice in a prism, and the shape have a visible length between these 2, known as the height

Step-by-step explanation:

Hope this helps

4 0

3 years ago

The area of the region in the first quadrant between the graph of y = k*sin(x) and x-axis (where k > 0 ) on the closed interv

astraxan [27]

Note that $0\le k\sin x\le k$ in the given closed interval, so the area is exactly given by the definite integral

$\displaystyle\int_0^\pi k\sin x\,\mathrm dx$

(no absolute values needed!)

Integrating gives

$-k\cos x\bigg|_{x=0}^{x=\pi}=-k(\cos\pi-\cos0)=-k(-1-1)=2k$

8 0

3 years ago