Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
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Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
Turn the text into an eqation:
48-x = 4x-7
5x = 55
x = 11
Answer:
5 km
Step-by-step explanation:
the scans means that any distance on the map is 50000 times larger in real life.
so, 10 cm on the map is
10×50000 = 500000 cm in real life.
now, we know that 100cm = 1 m
so, it is 500000/100 = 5000 m in real life.
and there are 1000 m in 1 km.
so, it is 5000/1000 = 5 km in real life
When you decrease 94% from 1000 grams you are left with 60 grams.
